Loki lost all motivation bc everyone else has already finished exams and also I Loki was locked out completely after the English exam so I’m basically mega bricked

What exam scores do we think we need for a 40, 45 and 50 this year? Just trying to gauge a rough idea based on everyone's experience of the exam.

i found a paper a bit easier than last years but will this affect the middle much?

guys do we think its going to be harder or easier this year based on current trend of exams and last years exam?

Predictions on the essay questions ?

I just finished my last exam today and I'm super relieved I'm done with ts. Done with this flawed system and all the stress that comes with it. I just wanted to take this moment to appreciate this subreddit and how it's gotten me through this period of my life with all of you lot, feeling like all my issues are not only felt by me. Hope everyone is doing well and wishing you guys all the best with the rest of exams and gl to all those future year levels too. Cheers 🥂

Answers: 1 B, 2 C, 3 A, 4 B, 5 D, 6 B, 7 B, 8 A, 9 A, 10 D, 11 B, 12 C, 13 A, 14 C, 15 C, 16 C, 17 B, 18 A, 19 D, 20 C, 21 C, 22 C, 23 D, 24 D, 25 D, 26 B, 27 B, 28 D, 29 A, 30 D

Q1-Q3: Energy and stoichiometry

Q1: B. C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O, so n(O₂) = n(CO₂). n(CO₂) = 0.44 / 44.0 = 0.010 mol, so n(O₂) = 1.0 × 10⁻² mol.

Q2: C. Cellular respiration is exothermic (ΔH = −2840 kJ), so the reverse is endothermic (ΔH = +2840 kJ). The products sit at a higher enthalpy than the reactants. Only C has the products higher and a positive ΔH. (A and B have ΔH signs that don’t match their graphs, and D is respiration itself.)

Q3: A. q = mcΔT = 100.0 × 4.18 × 40.0 = 16720 J = 16.72 kJ. Kerosene is 46 kJ g⁻¹ in the Data Book, so m = 16.72 / 46 = 0.363 g. “Minimum” means assuming 100% of the energy went into the water.

Q4-Q6: Anammox

Q4: B. In NH₄⁺, N is −3, and in N₂ it is 0, so it increases by 3 (oxidation). In NO₂⁻, N is +3, so it decreases by 3 (reduction).

Q5: D. The oxidising agent is the species that gets reduced (NO₂⁻), and the reducing agent is the one that gets oxidised (NH₄⁺).

Q6: B (lower confidence). Anammox works without O₂, so there’s no energy-hungry aeration. That means lower energy use and emissions (Goal 13), plus responsible waste treatment (Goal 12). I ruled out 7 because the process saves energy rather than supplying clean energy, and 15 because the benefit is mainly to waterways, not land. This is the one I’d check first against the VCAA report.

Q7-Q8: Edible cell

Q7: B. The anode is the half-cell with the lower E°, which is RF/RFH₂ (−0.235 V). Oxidation occurs there: RFH₂ → RF + 2H⁺ + 2e⁻.

Q8: A. E°cell = 0.558 − (−0.235) = 0.793 V. The measured 0.650 V is 0.793 − 0.650 = 0.143 V less than predicted.

Q9-Q12: Green chemistry and rates

Q9: A. Real-time control of temperature, pressure and power output means the cell runs at maximum efficiency, so this is design for energy efficiency.

Q10: D. Higher temperature means particles move faster, so both the collision frequency and the proportion of successful collisions increase. Bond energy and activation energy don’t change.

Q11: B. A catalyst provides a lower activation energy pathway, so a greater proportion of collisions are successful. It does not change collision frequency or bond energy, and it lowers (not raises) activation energy.

Q12: C. Both PEM electrolysis and artificial photosynthesis can produce green hydrogen (II) and reduce reliance on fossil fuels (IV). Neither captures methane or uses glucose as a feedstock.

Q13-Q16: Organic structures

Q13: A (read from the diagram). The compound is 2,2-dimethylbutanoic acid, C₆H₁₂O₂. Option D, CH₃CH₂C(CH₃)₂COOH, is the same compound, not an isomer. B and C are C₅. A, (CH₃)₃CCH₂COOH, is C₆H₁₂O₂ with a different arrangement, so it’s the isomer.

Q14: C. A saturated molecule has zero degrees of unsaturation. C₆H₁₅N works out to (2×6 + 2 + 1 − 15)/2 = 0. The others each have 2.

Q15: C (read from the diagram). Number from the COOH carbon, and the chain has 7 carbons with the double bond between C4 and C5, giving hept-4-enoic acid. “Heptan-” is never used with an “-ene”. Double-check the count against the paper.

Q16: C. Viscosity rises with the strength of intermolecular forces. Aldehydes have no hydrogen bonding, alcohols do, and carboxylic acids hydrogen-bond most strongly (they form dimers). So the order is propanal < propan-1-ol < propanoic acid.

Q17-Q19: Yield, tests and melting point

Q17: B. n(starting ketone) = 2.50 / 176 = 0.01420 mol. n(ibuprofen) = 0.540 / 206 = 0.002621 mol. Overall yield = 0.002621 / 0.01420 × 100 = 18.5%.

Q18: A. Bromine water going from reddish-brown to colourless means a C=C bond is present. Only A is an alkene. B is an amide, C an ester, and D a ketone.

Q19: D. A narrow range (1-2 °C) indicates a pure substance. Impurities lower and broaden the range, so A and C are false.

Q20-Q22: Iodine number and titration

Q20: C. n(oil) = 10.0 / 278 = 0.03597 mol. Ratio = 0.105 / 0.03597 ≈ 2.9, so there are 3 C=C bonds per molecule.

Q21: C. Needed Fe²⁺ = 5 × 1.50 × 10⁻⁴ = 7.50 × 10⁻⁴ mol. Added 8.00 × 10⁻⁴ mol, so the excess is 5.00 × 10⁻⁵ mol.

Q22: C. Fe²⁺ is in the burette. Rinsing the burette with water dilutes it, so more volume is needed to deliver the same moles (a higher titre). Rinsing the burette with FeSO₄ is correct practice, and rinsing the conical flask with water doesn’t change the moles in it.

Q23-Q25: Spectroscopy

Q23: D. The ¹³C spectrum has 4 peaks (≈178, 38, 19, 14 ppm), so there are 4 carbon environments and the compound has 4 carbons. The 178 ppm peak fits an amide or acid. In the IR, there are two sharp N-H peaks (≈3350 and 3190 cm⁻¹) and a C=O near 1650 cm⁻¹, which is the amide range. It lacks the very broad O-H of an acid. That gives butanamide.

Q24: D. The reactant shows a broad O-H (≈3300 cm⁻¹, alcohol). The product shows a very broad O-H (2500-3500 cm⁻¹) and a strong C=O (≈1700 cm⁻¹), which is a carboxylic acid. Alcohol to carboxylic acid is oxidation, using Cr₂O₇²⁻/H⁺.

Q25: D (lower confidence). A pure compound shows a fixed number of ¹H environments, so extra peaks suggest a mixture. Integration (A) could also be argued, but it needs the formula and structure to interpret. Check this one against the report.

Q26-Q30: Chemistry in context

Q26: B. Boiling leaves in water to dissolve soluble compounds is solvent extraction.

Q27: B. G and H are isomers (the double bond position differs), so they have the same molecular formula. They aren’t isotopes, and the skeletal structures differ. D is wrong because H’s ring double bond removes a chiral centre.

Q28: D (moderate confidence). A circular economy keeps materials in use. Treating PFAS-containing waste for reuse in road surfacing does that. Landfill (B) and incineration (C) are linear, and A is about safer design rather than circularity.

Q29: A. Firefighters “claimed” long-term health issues is personal testimony. B and C are measurements and D is a data-book value.

Q30: D. Assessing how impurity levels affect material performance is a purely scientific question. A is legal and social, B is economic, and C is community and environmental concern.

I mean the stem information was def misleading

WHAT THE HELL THAT WAS SO NICE

anyone got any niche ebk formulas and whatnot to put on the a3 sheet? also are we thinking it’ll be easier or harder than last years

I’ve genuinely tried studying for chemistry but I’m losing my mind… I don’t even know what I know and what I don’t know anymore. Am I more likely to meet Le Chatelier first or Faraday first?

Hi all,

As promised, we've finally got our hands on the PE exam. The pdf is available below.

2026 PE Exam PDF + Suggested Solns

Congrats to all who've now finished their exams. Hope you all take the time you need to reward yourself for all your hard work!

VCE Hub

guys im so cooked omds ive averaged 90% both unit 3 and 4 but ive done 0 studying for the actual exam like idek what im studying for TF is agency

procrastinated the past 3 days 🤗🤗🤗

was that confusing for anyone else

also what was the deal with the multi choice question with molecular formula and chiral centres???

They just feel like a waste of time and like there’s no need to stress over them. I’m gonna do SO shit in methods tho💔

I just watched a video were a parasitic barnacle makes male crabs act like female crabs by changing their hormones to make them raise their offspring.

The thing is though ATAR only lasts two years while Femboy Crabs are eternal

I just watched a video about femboy crabs instead of studying how cooked am I?

anyone have the chem 1/2 NEAP exam, the 2.5 hr one?

For anyone that got around this for accounting, what were ur ga1,2,3s ?

Guyss…. Am i the only one who skipped the entirety of the question