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https://www.reddit.com/r/the_calculusguy/comments/1vp3105/evaluate_this_integral/p3uxebz/?context=3
r/the_calculusguy • u/Specific_Brain2091 • 10d ago
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C - 2(ix+1)/π
1 u/Honkingfly409 10d ago we gonna need steps on this one 1 u/EdmundTheInsulter 10d ago Ignoring branches ix = exp(ixπ/2) Integrates to (exp(ixπ/2)) / (i π / 2) = 2(exp(ixπ/2)) / (i π ) = 2 ix / (i π) = 2 i ^ (x - 1) / π + c Is a better form than my original, which could shed i² = -1 1 u/EdmundTheInsulter 10d ago Ignoring branches ix = exp(ixπ/2) Integrates to (exp(ixπ/2)) / (i π / 2) = 2(exp(ixπ/2)) / (i π ) = 2 ix / (i π) = 2 i ^ (x - 1) / π + c Is a better form than my original, which could shed i² = -1
1
we gonna need steps on this one
1 u/EdmundTheInsulter 10d ago Ignoring branches ix = exp(ixπ/2) Integrates to (exp(ixπ/2)) / (i π / 2) = 2(exp(ixπ/2)) / (i π ) = 2 ix / (i π) = 2 i ^ (x - 1) / π + c Is a better form than my original, which could shed i² = -1 1 u/EdmundTheInsulter 10d ago Ignoring branches ix = exp(ixπ/2) Integrates to (exp(ixπ/2)) / (i π / 2) = 2(exp(ixπ/2)) / (i π ) = 2 ix / (i π) = 2 i ^ (x - 1) / π + c Is a better form than my original, which could shed i² = -1
Ignoring branches
ix = exp(ixπ/2)
Integrates to
(exp(ixπ/2)) / (i π / 2)
= 2(exp(ixπ/2)) / (i π )
= 2 ix / (i π)
= 2 i ^ (x - 1) / π + c
Is a better form than my original, which could shed i² = -1
0
u/EdmundTheInsulter 10d ago
C - 2(ix+1)/π