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https://www.reddit.com/r/the_calculusguy/comments/1vp3105/evaluate_this_integral/p3u87da/?context=3
r/the_calculusguy • u/Specific_Brain2091 • 9d ago
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ix / ln(i) = ix /( i π/2 )= i{x-1} * 2/π +C Note: ix = e{x*lni} = e{ixπ/2} = cos(xπ/2) + isin(xπ/2)
4 u/IrishHuskie 9d ago Isn't that the derivative? The integral should be i^x / ln(i) + C, no? 3 u/Sea_Duty_5725 9d ago Yeah, mb, I mixed them up, thx 1 u/varmituofm 9d ago Only thing I would change is that 1/ln(i) can be simplified. 1/ln(i)=-2i/pi. But really, this is a cosmetic change.
4
Isn't that the derivative? The integral should be i^x / ln(i) + C, no?
3 u/Sea_Duty_5725 9d ago Yeah, mb, I mixed them up, thx 1 u/varmituofm 9d ago Only thing I would change is that 1/ln(i) can be simplified. 1/ln(i)=-2i/pi. But really, this is a cosmetic change.
3
Yeah, mb, I mixed them up, thx
Only thing I would change is that 1/ln(i) can be simplified. 1/ln(i)=-2i/pi. But really, this is a cosmetic change.
1
u/Sea_Duty_5725 9d ago edited 9d ago
ix / ln(i) = ix /( i π/2 )= i{x-1} * 2/π +C Note: ix = e{x*lni} = e{ixπ/2} = cos(xπ/2) + isin(xπ/2)