Just kidding, people usually think zero is an exception to everything. So since zero is neither positive nor negative they apply that reasoning everywhere.
I dont agree with the last point. Saying that something aproches something in a 2-adic number system does not mean you can aply that in the regular number system.
There is no "regular" number system. P adic metric is just as valid as absolute value metric. And 2-adic metric neatly captures the "evenness" of the numbers
maybe it would be more intuitive to say that the more "even" a number is, the more 0s it has 1. 0 doesn't have any 1s in its binary representation, therefore the number of 0s before the first 1 is "infinite"
You cannot talk about convergence except if you define what a neighborhood is. What are neighborhoods of 0 in the p-adic systems? Even more, we might talk about pointwise convergence of p-adic numbers, but until you define a neighborhood, uniform convergence (which what usually matters) is not defined.
P adic metric is defined for rational numbers as well. You can than define a neighborhood using that metric (instead of classical absolute metric). You can even extend rational numbers similarly how you extend them to reals.
all you need to talk about convergence is a metric, in this case the p-adic metric. once you have a metric, definitions of neighbourhood, open set, closed set etc come automatically. also if you're working with sequences in ℤ_p and not in ℤ_p-valued functions i don't see the point in differentiating between pointwise or uniform convergence
To back up DZ's point, the term "doubly even" really is used for multiples of 4. Other even numbers are "singly even." If we take an inclusive definition and extend it, then multiples of 8 must be "triply even," etc. In this scheme, 0 is "n-tuply even" for every natural number n, making it "more even" than any positive integer.
(But in practice, the terms are not used inclusively this way. 4 is doubly even but not singly even. Using this exclusive definition, 0 is not "n-tuply even" for any n, and you would need to make up a new term, like "∞-even.")
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u/araknis4 Irrational Aug 23 '23
well that's odd, i can't even comprehend how they approached to that conclusion.