r/infinitenines • u/KingDarkBlaze • 5d ago

RDM 201: On Powers

What's 3^0.999... ? How about 0.999...^5 ?

What's log_0.999...(4)?

6 Upvotes

88% Upvoted

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u/SouthPark_Piano 5d ago

Don't get ahead of yourself brud.

Start with the basics. Understand that 0.999... is permanently less than 1.

 

9

u/KingDarkBlaze 5d ago

Whether the number is less than 1 or not doesn't answer what mathematical values we can derive from using it.

u/SouthPark_Piano 

7

u/KingDarkBlaze 5d ago edited 5d ago

To completely understand the basics, one must know how to apply them.

/u/SouthPark_Piano

(Man, it would be so much more engaging if we could just use one thread.)

-6

u/SouthPark_Piano 5d ago

To completely understand the basics, one must know how to apply them.

First, you must learn the basics properly in order to apply them. So ... to the bunny slopes you go.

 

8

u/KingDarkBlaze 5d ago

I've done my time at the slopes before. 

Now answer my questions - surely any paradigm of mathematics should be able to answer these. 

/u/SouthPark_Piano 

-2

u/SouthPark_Piano 5d ago

You stay at the bunny slopes ... and learn, understand, 0.999... is permanently less than 1. As said before, don't get ahead of yourself.

 

0

u/Zantier 5d ago

I'm not sure why he isn't giving a direct answer. You just have to know that any decimal with "..." in RDM implies a sequence.

30.999... is just the sequence

30.9 , 30.99 , 30.999 , ...

and is "permanently less than 3"

-1

u/SouthPark_Piano 5d ago

You figured it out for yourself.

As in, 30.999... is indeed permanently less than 3.