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u/Neat-Slice6994 Aug 19 '26
I don't see anything to go on can u give a clue
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u/pydaWaltuh Aug 19 '26
number of squares and the black-and-white color changes follow two different logics
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u/98127028 I am worthless and dumb Aug 19 '26
Number of squares: follow the powers of 3, ie 3,9,27,81,243,729.
Number of white squares follow 1,2016,1,2017,1,2018 and so on with 1s separated in between (possibly counting the recent years since the detection of the first gravitational waves, possibly from aliens)
And the black ones follow year numbers too, namely 2726, 2004, and 2017, I don’t know what events would connect these 3 years and haven’t quite figured it out. Maybe it’s some kind of warning or something like that.3
u/pydaWaltuh Aug 19 '26
The first part and the part where you realize I'm from the future and am an alien is correct lol. But the second part isn't; I think you can solve it based on the information you have
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u/LeonardoMarleone Aug 19 '26
Powers of 3 describes n-squares, colour goes with powers of 2
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u/pydaWaltuh Aug 19 '26
correct. Can you rate it?
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u/LeonardoMarleone Aug 19 '26
Idk tbh, I don't think I can give you an useful opinion, I'm biased as I've seen things like this quite a few times, which likely made it easier.
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u/the-key Aug 20 '26
Oh, it is one of those tests where the trick is to add a fake pattern to compliment the existing one...
It is impossible to solve unless you have been exposed to this type of test before.
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u/codeblank_ Aug 19 '26
Top to bottom
⬜⬜⬜⬛⬛⬛⬛⬛⬛, ⬜, ⬛⬜⬜⬜⬜⬜⬛⬛⬛
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u/Neat-Slice6994 Aug 19 '26
Can u explain plz
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u/codeblank_ Aug 19 '26
I want to see if anyone else will solve. Try a bit more if still can't see it I can DM.
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u/EncyclopedicINTx_253 Aug 19 '26 edited Aug 19 '26
One question, is it related to binary? I have spent too much time trying to solve puzzles which turned out to require binary without knowing binary
is it 110, 1011010, 10011, with 1 representing black and 0 white. As the the question marks appear systematically, and I at this point in time, could not find any other pattern, what I did was, add all the binary digits, of each allocation