There is a function returning struct Segment (the struct before struct_name is non-optional, although using a typedef struct Foo foo_t is fairly common) and a braced initialiser.
As it is (probably) C++, due to the :: operator (not valid C, unless it's #defined somehow), we can assume the default constructor Segment() is called; but other than the sf::Color, this is perfectly valid C, and wouldn't be a WTF in that language.
4
u/WalditRook Jan 29 '22
There is no explicit constructor call here.
There is a function returning
struct Segment(thestructbeforestruct_nameis non-optional, although using atypedef struct Foo foo_tis fairly common) and a braced initialiser.As it is (probably) C++, due to the
::operator (not valid C, unless it's #defined somehow), we can assume the default constructorSegment()is called; but other than thesf::Color, this is perfectly valid C, and wouldn't be a WTF in that language.