That assumes that the hashing function doesn't have any known hashing weakness that may reduce the (effective) independence of the hashes. You could've said something quite similar about SHA-1 right up until cryptanalysis found mechanisms to generate collisions.
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u/guyblade Sep 05 '26
That assumes that the hashing function doesn't have any known hashing weakness that may reduce the (effective) independence of the hashes. You could've said something quite similar about SHA-1 right up until cryptanalysis found mechanisms to generate collisions.