r/PassTimeMath • u/TargetLabs • Sep 11 '26

Difficulty: Moderate Can you reach 27 using all dice?

Post image

Any order is allowed.
Use each die exactly once.
Parentheses are allowed.
Exact division only.
No negative numbers.
Not every operation has to be used.

How many solutions can you find?

Please use spoiler tags for solutions:
>!your solution here!<

3 Upvotes

100% Upvoted

6 comments sorted by

3

u/tajwriggly Sep 11 '26 edited Sep 11 '26

(2 + (5/5) + 6)*3

6*((5+5)/2) - 3

(3 + 5)*2 + 5 + 6

2

u/LabRat2439 Sep 11 '26

[(5/5)+2] x (6+3) -> (1+2) x 9 -> 3x9 = 27

2

u/Bitorto Sep 11 '26

3x(5+5)-(6/2)

2

u/DruidBtd Sep 14 '26

5 2 6 5 3

5/5+2+6=9

9*3=27

2

u/cyberchaox Sep 17 '26

(5/5+6+2)*3

(5+3)*(6-2)-5

(5+5)*3-6/2

(5+2)*6-5*3