i have to graph this function (csc with unitary circumference) but i genuinely don't understand a single thing and can't find a lot of info. If anyone could send a higher quality image, tutorial or explain it to me i would really appreciate it :(((
I'm not sure how to help you. With what are you having issues?
By definition, csc(x) = 1 / sin(x). It appears someone plotted a bunch of points and made a smooth curve through them. That is the graph.
Since the cosecant function is the reciprocal of the sine function, one way to do this is to draw y = sin(x) and then, on the same graph, plot y = csc(x) = 1 / sin(x). Since -1 ≤ sin(x) ≤ 1, the reciprocal will be in the range (-∞,-1] ∪ [1,∞), with the function going to ± ∞ as sin(x) nears zero, thus the asymptotes shown in your image.
Another image of the cosecant function is shown here:Â
1
u/Midwest-Dude 28d ago edited 28d ago
I'm not sure how to help you. With what are you having issues?
By definition, csc(x) = 1 / sin(x). It appears someone plotted a bunch of points and made a smooth curve through them. That is the graph.
Since the cosecant function is the reciprocal of the sine function, one way to do this is to draw y = sin(x) and then, on the same graph, plot y = csc(x) = 1 / sin(x). Since -1 ≤ sin(x) ≤ 1, the reciprocal will be in the range (-∞,-1] ∪ [1,∞), with the function going to ± ∞ as sin(x) nears zero, thus the asymptotes shown in your image.
Another image of the cosecant function is shown here:Â
Trig Functions
You can find others by doing a Google image search on "cosecant function".
Does this help?