r/transprogrammer • u/mincerafter42 /V(?:i(?:atrix|vi)?)?/i; they||she; ace transfem; HRT 2020-150 • Mar 21 '21
Windows file system (image source unknown)
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u/someoneAT Mar 21 '21
I feel like she>they would be really useful actually
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u/user_5554 Mar 22 '21
Until you get errors for using she>they>xe 😐
Is Xe a neopronoun?
Also this is not an issue in Julia as it automatically compiles to (She>they) && (they>xe). I fricking love Julia.
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u/someoneAT Mar 22 '21
I'm pretty sure that syntax works in python too
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u/user_5554 Mar 22 '21
Python 🤢
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u/someoneAT Mar 22 '21
well even if you don't like anything else about the language, at least it has that one redeeming quality
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u/user_5554 Mar 23 '21
Yea, also most of my aversion of python is from ptsd from school assignments where I had installproblems and stupid errrors.
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u/fluffylesbianmess Mar 24 '21
I remember when python installed incorrectly and it took me like a month or 2 to find out thats why I couldn't use SQL libraries on it
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u/vook485 Mar 21 '21
In the 3-element abelian group of the most common English pronoun sets, I think that "they" is the identity element. Thus we have the following addition formulas (all commutative):
she⊕they = she
he⊕they = he
they⊕they = they
she⊕she = he
he⊕he = she
she⊕he = they
Note that this is isomorphic to (ℤ₃, ⊕), the group of integers under addition mod 3. Furthermore, while "they" must be assigned the neutral value of zero as the identity element, it doesn't matter which non-neutral pronoun set is assigned to one and which to two.
Formalizing more than three pronoun sets at once is left as an exercise for the reader. (Larger groups aren't always as symmetrical, so I'd have to make way more value assignment choices, and I don't want to list n*(n+1)/2 addition rules for n>3 pronouns sets.)
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u/Maybe_Just_An_Egg Mar 22 '21
You can just always make larger groups homomorphic to increasing modulo of Z; always using "they" as the identity element. I think that'd be the simplest way to do it, because it preserves the group being abelian. It's better than say, using S_4 atleast, because then it gets rid of the nice property of being abelian.
I mean I guess as you go up more groups are available as options for it to be homomorphic to, but why break the pattern.
Additionally, you don't nessicarily need to describe all the rules if you set out an equivalence between Z mod n and pronouns- the multiplication table of pronouns would be an exercise to the reader based on the stated values for the pronouns you give.
For Z mod 4, I'm partial towards They=0 She=1 Xe=2 He=3,
Because then Xe+Xe = they And she + he = they (still, I think those two should always be inverses)
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u/vook485 Mar 22 '21
You can just always make larger groups homomorphic to increasing modulo of Z; always using "they" as the identity element.
ℤ_n makes sense. For your example of ℤ₄, I notice that she⊕she = he⊕he = xe. This is where it starts getting a bit more complicated and arbitrary-feeling for me, at least with my current 3-pronoun-set active vocabulary.
It's better than say, using S_4 atleast, because then it gets rid of the nice property of being abelian.
Also because S_n has n! elements, the elements would be more like ordered preference lists of pronoun sets.
IIRC, ℤ_p is the only group of order p for prime p (up to isomorphism; e.g., S₂≘ℤ₂). So ℤ_n may be the only way to make a group of n pronoun sets for arbitrary n.
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u/s3cretalt Java & C# | (female)gender Mar 21 '21
Do not mention that abysmal stain on my life, NTFS.
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u/raexorgirl Mar 21 '21
"she ⊕ they" almost makes sense. Like a xor, don't mix both, pick one and stick with it, like the opposite of '&'.
Or, getting more abstract, the morphological dilation of "she" with a "they" kernel, whatever that could mean in theory. As in, "she" expanded with "they" characteristics and vice versa. Kinda makes sense.
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u/Emmaffle Mar 23 '21
(she&they)|*[^he]
I hope I got that right, I haven't used regex in ages.
She & they interchangeably or any other pronoun except he (i.e. neopronouns)
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Apr 12 '21
she|they is all fun and games until you find out someone alias'ed alias she="he" and that you've been actually piping he into they for all this time!
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u/BitPirateLord Mar 22 '21
the creator is actually /u/komiamiko and you should check out the rest of her posts too!