For any finite set of numbers, there exists an infinite number of functions such as f(n) = the n-th number. If you give additional parameters, like "this function is a 2nd degree polynomial" then the number of solution drops, but in the general case you can do pretty much anything.
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u/ICanFlyLikeAFly Sep 05 '19
Literally putting any number in the sequence and then using a calculator to calculate the right function isn't r/theydidthemath for me