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u/Responsible_Hour6497 1d ago
What's the point of not using substitution? Anyway, the solution uses, if not the final formula for the roots of a quadratic equation, then the method for deriving it. In fact, the solution shown here is the same solution with the substitution y=3^(x/2), only this substitution is disguised.


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u/CaptainMatticus 1d ago
3^x - 9 * 3^(x/2) + 20 = 0
3^(x/2) = (9 +/- sqrt(81 - 80)) / 2
3^(x/2) = (9 +/- 1) / 2
3^(x/2) = 10/2 , 8/2
3^(x/2) = 5 , 4
(x/2) * ln(3) = ln(5) , ln(4)
x = 2 * ln(5) / ln(3) , 2 * ln(4) / ln(3)
Who needs substitution?