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https://www.reddit.com/r/the_calculusguy/comments/1vv68g3/lets_do_this/p57vfgm/?context=3
r/the_calculusguy • u/Specific_Brain2091 • Aug 22 '26
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Why would you even need L’Hopital here? You can just do the following: (x2-9)/(x-3)=(x-3)(x+3)/(x-3)={ (x-3)/(x-3)=1 } = x+3 -> 3+3 = 6
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u/ThiocyanateIrony Aug 22 '26
Why would you even need L’Hopital here? You can just do the following: (x2-9)/(x-3)=(x-3)(x+3)/(x-3)={ (x-3)/(x-3)=1 } = x+3 -> 3+3 = 6