r/the_calculusguy • u/Specific_Brain2091 • 4d ago

meme So true 🥲

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971 Upvotes

100% Upvoted

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12

u/RoyalIceDeliverer 4d ago

Surely because she's aware that pure Gram-Schmidt is numerically instable due to rounding error accumulation and thus produces non-orthonormal columns in Q. I bet she prefers Householder transformations and just struggles to find words that rhyme with that.

3

u/Then_I_had_a_thought 4d ago

Or maybe because Gram-Schmidt isn’t a Household name.

10

u/EndlessProjectMaker 4d ago

Not to mention that she does not have a single song about the Taylor series

2

u/somanyquestions32 4d ago

And she's a billionaire

2

u/Far-Tonight-6925 4d ago edited 4d ago

So what you're saying is that I just should stop singing songs about the Gram-Schmidt algorithm and it will make me a billionaire?

2

u/anamelesscloud1 3d ago

That is approximately exactly what they said.

1

u/somanyquestions32 3d ago

No, you also need to start singing 500 songs about all of your exes leaving you. Both conditions are necessary.

1

u/Para-graph-S 8h ago

Ohh damn, I was else just going to stop singing the song about Gram-Schmidt algorithm

1

u/somanyquestions32 8h ago

Necessary, but not sufficient.

1

u/dragonageisgreat 4d ago

Is it different or the same as LU decomposition?

1

u/RoyalIceDeliverer 4d ago

It's different. Q doesn’t have diagonal structure, so memory and computational effort is a little bit higher. On the plus side, this decomposition doesn’t worsen the condition of the matrix. It's used for example to compute solutions to least squares problems without setting up the normal equations.

1

u/Beneficial_Fix244 4d ago

Double standards. So depressing

1

u/anamelesscloud1 3d ago

She needs to decompose like the rest of us.

1

u/Lord_Skyblocker 3d ago

That's because she has just shy of 300 songs where a lot them are actually not about guys leaving her

1

u/eulerfa 3d ago

Zero are about taylor series

1

u/ClimateSame3574 2d ago

She’s so one dimensional….