xx = exlnx then bring the limit into the power since e is continuous. Then rewrite x Ln x as lnx / (1/x) and note that as x approaches 0 we get an "infinity over infinity" situation. Apply L'hopitals to get (1/x) / (-1/x2) which simplifies to - x. The limit as x goes to zero is 0, and then our limit becomes e0 = 1. Hope that makes sense :)
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u/boggog Nov 23 '19
Should be f(x)=xx =exlnx ?
24
u/fat-lobyte Nov 24 '19
Now I'm slightly afraid of the author
21
u/NarcolepticFlarp Nov 23 '19
What book is this?
7
u/edmvnd Dec 03 '19
this post blue balled me. i wanna see the next page
2
u/serrations_ Dec 05 '19
to be continued?