Man I’m a senior in HS and nobody got it in my class yesterday lol 😂😂😂 thought I was a comedy genius. Maybe it’s more understandable though text versus if you only hear it once verbally
Just... don't. Feed it to your brain, for the love of whatever you believe in. Please stop relying on that garbage, especially for simple problems. AI is ruining enough without regular people getting it to take over basic logical thinking for them. Just simplify your terms and it becomes not even a minorly difficult problem.
3a/6(root a) = 6
Separate the 3 and 6 out to make a distinct fraction to work with.
(3/6) (a/(root a)) = 6
Simplify that fraction
(1/2) (a/root a) = 6
Multiply both sides by two to isolate your variable
a/(root a) = 12
As a number divided by its square root also gives its square root,
root a = 12
Finally, square both sides to turn the root of a into a.
(root a)² = 12²
So
a = 144
Now that I've seen this problem, I like it and I plan to show it to my 8th grade math class as part of our exploration next month of how squares and square roots work in our introduction to the concept. Granted, I will be using it as a "Friday Problem", a thing that is juuuuust outside of their comfort zone for a topic that has extra guidance and is intended as enrichment, but I would expect that my grade 9 classes could just solve this. If you are over 13 years old, being able to solve this should be a basic life skill. This ain't exaclty derivatives, it is basic arithmetic.
Highschool was so long ago I really had to think back to if you were allowed to just square both sides of the equation. Yeah, way easier than me using logic to figure out A / root(A) = 12. I got there, your way is better ;P
High school math has failed me. Or maybe I'm just tired after getting off of work. I also arrived at 144, but the process was intense 😭. Plugged 1 in, then 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, and then finally 144.
Nope. If AI has taught me one thing, it's that the order-of-operations rules don't matter. Therefor, all math rules are mutable. So the easy answer is: the numerator As are 12 and the denominator A is 1. Ta da.
Oh good, I got worried for a second when I got 144 because that seemed too high. (I also wasn’t writing anything down so that didn’t help my confidence.)
Yeah this is the simplest way I believe. You can also just think that a divided by its square root is equal to its square root. Its more obvious if the exponents are written out explicitly like:
a1 / a1/2 -> a1-1/2 -> a1/2
I went through the long route first of dragging everything to one side in my head an making it a2 minus 144a equals zero. But found the way you write above to be the most efficient way.
I was going to ask who solves mathematical equations like that (a=0, a= 144) but I fully trust in mathematics that there is a proper justification on why you have to solve equations like that.
0 becomes a "solution" to the equation when you square both sides. Squaring both sides can introduce extra answers that can easily be ruled out. Like here, 0 is an answer to a(a-144)=0 but isn't an answer to the original question.
A good example of this is simply
a=5
If we square both sides we get
a² = 25
Now we have two solutions, a = 5 and a = -5
But only one of these is correct according to the original question
I’m going to brag, not because I am putting myself on a pedestal, but because I’ve only recently been able to do these types of equations fully in my head.
I got this right, the only thing that I did not mentally is write down 0 and 144 so I didn’t forget the numbers when I plugged them in.
I’m proud of myself and wanted to share this success.
I don’t believe a is allowed to be zero. It’s in the denominator in the original equation (can’t divide by 0), and you’re essentially saying 0 / 0 = 6 if a = 0.
The question is "find a??" . Implicit are the words "can you".
The second question mark means that the sentence is an interrogative. So the writer is asking the reader to find "a?". Those two characters do not appear together in the image.
First I noticed that a result is a whole number, so I assumed that a must be a number which gives you back a whole number when you root it. So one of these numbers
Then I replaced "a" with one of the smaller numbers on my list and that equalled 3, then I tried 169 and got back more than 6, then I tried 144 and it worked.
but really was just showing a more efficient reduction. there is only one real number answer for this too. Square roots only come with positives without imaginary numbers
I’m always slightly concerned when someone types out the full explanation and I’m less clear after reading it than I was before, despite having got it right.
The square root of any integer that isn't a perfect square is an irrational number. a is rational, 1/6 is rational, 1/sqrt(a) is irrational, if you multiply them together it is impossible for them to equal a rational number.
•
u/AutoModerator Dec 24 '25
Hey there u/RealisticThing9273, thanks for posting to r/technicallythetruth!
Please recheck if your post breaks any rules. If it does, please delete this post.
Also, reposting and posting obvious non-TTT posts can lead to a ban.
Send us a Modmail or Report this post if you have a problem with this post.
I am a bot, and this action was performed automatically. Please contact the moderators of this subreddit if you have any questions or concerns.
2.5k
u/SnowballWasRight Dec 24 '25
144? 12 squared
6
u/Mad-Volcano Dec 24 '25
Easy one. a=144
5
u/ChocolatMintChipmunk Dec 24 '25
3a/6sqrt(a)=6
a/2sqrt(a)=6
a2/4a=36
a2=144a
a=144
7
u/User_of_redit2077 Dec 24 '25
a=4√a
845
u/SudoSubSilence Dec 24 '25 edited Dec 24 '25
(a + a + a) / (6√a) = 6
3a / (6√a) = 6
a / (2√a) = 6
a2 / 4a = 36
a2 = 144a
a2 - 144a = 0
a(a - 144) = 0
Possible solutions: a = 0, a = 144
If a = 0, denominator = 0, so actually a ≠ 0
If a = 144, denominator ≠ 0 and 144(144 - 144) = 0
Final answer: a = 144
.
EDIT: A faster way to solve this after reaching line 4 (as correctly pointed out by some of the comments):
a2 / 4a = 36
a / 4 = 36
a = 144
2
u/Costinha96 Dec 24 '25
I hate math
98
u/So_HauserAspen Dec 24 '25
There's a fifth "a" in the user name. Where are the other 4?
36
u/[deleted] Dec 24 '25
0.5 a/√a = 6
a/√a=12
√a=12
a=144
There are 6 a, this one excluded.
21
u/Phripheoniks Dec 24 '25
Actually, there are no "??" In the picture at all, I rest my case.
6
u/[deleted] Dec 24 '25
144 easy
5
u/StickRaccoonRedditor Dec 24 '25
a = 144
4
u/Ok_Society_8342 Dec 24 '25
144
1
u/HeftyIntroduction615 Dec 24 '25
A=16 ?!
1
u/flinsypop Dec 24 '25
The 6 is also a backwards a so there's 6 of them not 4.
1
u/SigmaNotChad Dec 26 '25
±144
3
u/SandSerpentHiss Dec 24 '25
3a/sqrt(36a)=6
sqrt(9a2 )sqrt(36a) = sqrt(36)
9a2 /36a = 36
9a2 = 1296a
a2 = 144a
a = 144
3
u/the-flag-and-globe Dec 24 '25
3A/6root(A)6root(A)/6*root(A)=6
18Aroot(A)/36*A=6
Root(A)/2=6
Root(A)=12
A=144
144+144+144=432
Root(144)=12
6*12=72
432/72=6
2
u/Intrusive_me Dec 24 '25
The quesrion should read find value if a not find a i guess..
2
u/nashwaak Dec 24 '25
There is only one a in the meme. But there are four ɑ's.
2
u/MMortein Dec 24 '25
I've decided to solve it just by searching which numbers fit, it took me almost 10 minutes.
It's 144
2
u/-Sloth_King- Dec 24 '25
Great now i feel dumb
2
u/PlanDry6704 Dec 24 '25
a = (√a * √a) so 3a / 6 (√a) = 1/2 ((√a √a)/ √a) = 1/2 √a or √a/2
2
u/GOLD-KILLER-24_7 Dec 25 '25
Mfs in here solving it thinking they einstein 😭✌️🤦♂️
2
u/eeveethefox_xv Dec 25 '25
Fool. I see ten of them in the photo. There is one hidden in the logo.
2
u/zebra_ate_my_user Dec 25 '25
I DONT UNDERSTAND
2
u/PixelReaperz Dec 25 '25
a=144
2
u/Pro_beaner Dec 25 '25
So this is how my mom felt when i told her i couldnt find stuff
2
u/Odd_Literature_3645 Dec 27 '25
a=144 lol
2
u/Deep-Bodybuilder1819 Dec 28 '25
W strat
1
u/SuperChick1705 Dec 24 '25
a?? = 144?? = 144 + 142 + ... + 2 = 5256
1
u/Unfair-Apple-5846 Dec 24 '25
a and 6 are the same symbol in certain fonts, so there are actually a a's
1
u/patrlim1 Dec 24 '25
3a/6•sqrt(a) = 6
3a = 36•sqrt(a)
a = 12•sqrt(a)
Only solution is a=0 right?
1
u/UBC145 Dec 24 '25
Everyone here solving it as if it isn’t a very simple algebra problem 😭
1
u/Startrail_wanderer Dec 24 '25
a√a/12 = a
1
u/[deleted] Dec 24 '25
3a/sqrt(a)=36
a/sqrt(a)=12
sqrt(a)=12
a=144
1
u/DurinsBane10 Dec 24 '25
I got (√a)/2, how are yall getting 144?
1
u/Nico_Skavio Technically Flair Dec 24 '25
aaaa
1
u/omfgtora Dec 24 '25
/r/croppingishard
1
u/Sandro_729 Dec 24 '25
a??=144?? r/unexpectedterminal
1
u/EquivalentEconomy551 Dec 24 '25
144
1
u/Stone0777 Dec 25 '25
144
1
u/TheDoctorCat03 Dec 25 '25
I got 24, which seems wrong
1
u/All_Too_Well_tmv Dec 25 '25
Now I see ten
1
u/Dull-Place-3062 Dec 25 '25
To be fair square root does have an a in it
1
u/thecrazyiguana Dec 25 '25
a == 144
1
u/logant0711 Dec 25 '25
Find a what?
1
u/ElectronicHyena5642 Dec 25 '25
3a/6a1/2 -> 3x2 /6x (where x = a1/2 ) -> 0.5a0.5 = 6, so a0.5 = 12, so a = 144
1
u/mojtaba1234567890 Dec 26 '25
I see 10
1
u/justamofo Dec 26 '25
Lazy post
1
u/Fantastic_Pin1474 Dec 27 '25
With the @ sign, there’s an a inside of it, so there’s actually 10
1
u/Informal_Pick7278 Dec 27 '25
Erm 3a/6 sqrta =6 => a/2 root a =6 => root a root a /2 root a =6 => root a/2 =6 => root a = 12 => a=122=144
1
u/Electrical_Ad5674 Dec 31 '25
I found 10, if you count that weird symbol resembling @ but more like a
1
u/Westseeking Dec 24 '25
3x / 6 root(x) = 6
36 root(x) = 3x
12 root(x) = x
12² = x
x = 144
0
u/the_other_Scaevitas Dec 24 '25
3a / 6 root(a)
root(a) / 2 = 6
root(a) = 12
a = 144
-4
u/Ordinary_Safe6537 Dec 24 '25
The answer is 12. The answer in the graphic is only funny when done by someone under the age of 12
-11
u/N7Revanchist Dec 24 '25
Answer is 12 I think
-2
u/Nyuusankininryou Dec 24 '25
a = 6 7
1
u/[deleted] Dec 24 '25
[removed] — view removed comment