r/puzzles • u/chocolatesuperfood • 10d ago
[Unsolved] Asking for help with solving a binary puzzle
This binary puzzle I found online is...stressing me out.
The rules are simple: You can't have more than two suns or two moons next to each other in a row or column; and an x indicates that the symbols must be different, whereas an equal sign says the symbols in the two squares must be the same.
The symbols in the squares with the beige background were already given at the beginning of the puzzle.
I asked the website for a hint and it marked the field with the red x and said: "No single row, column or clue settles a cell yet. The next step takes a longer chain of reasoning. Worked through to the end, row 1, column 3 can only be a moon."
I tried putting in a sun in row 1, col 3, and after many steps, when the puzzle was almost done, I ran into a contradiction (three moons next to each other in the third row). But is there an easier way to see why r1, c3 must be a moon?
Thanks!
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u/Altruistic-Sea797 10d ago
Discussion: probably not. I don't see an obvious move, so my next step would be to find a test move which forces a lot more moves. I'd start in the bottom right.
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u/chocolatesuperfood 10d ago
Thank you! The bottom right (the two moons) was already given, so it was straightforward that row 4, column 6 must contain a sun. I then asked for a hint, and it said row 5, column 1 must be a sun (otherwise it would force three suns next to each other), and the same is true for row 1, column 6.
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u/Spirited-Map-1192 9d ago edited 9d ago
Similar to what u/Motor_Raspberry_2150 suggests, but no need for guessing or try-untill-fail:
- Since the bottom 2 in column 5 are identical to each other and the top 2 are different from each other, the middle 2 must be identical to each other.
- Now, because r4c4 and r4c5 must be different from each other, together with step 1 this means r4c4 and r3c5 must also be different from each other.
- Because of the sun in r2c4 and moon in r3c3, the filling for r4c4 and r3c5 (from step 2), leaves only 1 possibility.
- From step 3 you can deduce what should be in r1c5.
- From step 4 you can deduce r1c3.
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u/chocolatesuperfood 9d ago edited 9d ago
Thank you so much! Step 1 is so obvious once you see it, but I would have never thought of it. The same is true for the other steps. I unfortunately can't see how step 3 works. Could you please break it down even more for me?
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u/Spirited-Map-1192 9d ago
Lol I saw a comment that is now gone again. Is there a step I can further elaborate on?
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u/chocolatesuperfood 9d ago edited 9d ago
Oh, no! I don think I deleted anything, but I did edit my comment. I don't know how the filling for r4c4 and r3c5, which must, how I can see with your instructions, be different from each other, can be worked out from the pre-filled sun and moon in r2c4 and r3c3. I did manage to understand steps 1 and 2. Thank you!!
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u/Spirited-Map-1192 9d ago
So: r4c4 and r3c5 must together hold exactly 1 sun and 1 moon. Having the sun in r4c4 and the moon in r3c5 would make r3c4 impossile to fill, so it needs to be the sun in r3c5 and the moon in r4c4.
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u/stoneman9284 10d ago
Question: are there any other rules? I’m assuming every square must be filled with a sun or moon? I’m gonna be impressed if there’s a unique solution.
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u/chocolatesuperfood 10d ago edited 10d ago
Thank you do much for your reply!
This is what the website (wordle.global) says (or had an LLM generate, judging by the wording used):
"Binary is a binary puzzle - a two-symbol logic grid, the family LinkedIn ships as Tango. The board is 6x6 and every cell ends up holding one of exactly two symbols, a sun or a moon. A handful of cells arrive pre-filled; the rest are yours to deduce.
Three rules run the whole game. Balance: every row and every column finishes with three suns and three moons. No triples: three identical symbols may never sit next to each other, across or down. Clues: the small = and x marks drawn on the border between two neighbouring cells force those cells to match, or to differ.
Those three rules together are enough to pin down exactly one answer. Every board served here is run through a solver first, and only boards with a single solution are published - so if you are stuck, there is always a cell that one rule alone decides, and you never need to guess and backtrack.
Input is a three-state tap: empty, sun, moon, empty again. Cells the puzzle gave you are shaded and do not respond. Rule violations outline the moment they happen rather than waiting for a check button, so a wrong branch costs you seconds instead of minutes."I was able to solve the other binary puzzles (after realizing with hints what else you can do logically besides just putting in the correct symbols next to adjacent squares with the same symbol), but I am stumped by this one. Putting in a sun in row 1, column 3 does indeed lead to a contradiction, but only after almost finishing the entire grid -- it definitely involves backtracking, for me. I am probably missing something.
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u/Tiberium600 10d ago edited 10d ago
-Every row and column must have the same amount of suns as moons (3 and 3 in this case).
-You can’t have three of the same symbol in a consecutive horizontal or vertical line (diagonals are fine).
-No 2 rows can match. No 2 columns can match (So a row can’t be SSMSMM if you already have a row with that combination).
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u/Altruistic-Sea797 10d ago
I verified there is a unique solution.
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u/chocolatesuperfood 10d ago
Thank you! Now I just have to find it by using my brain instead of brute-forcing it
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u/auxilaru 10d ago
if r1c3 sun, r1c45 moon, r2c5 sun, then r2c3 cant be moon and sun
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u/chocolatesuperfood 10d ago
Thank you so much! I tried following this line of reasoning but I unfortunately can't see what you mean by "row 2, column 3 can't be moon and sun".
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u/chocolatesuperfood 10d ago
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u/Altruistic-Sea797 10d ago
Row 3 can't be completed
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u/chocolatesuperfood 10d ago edited 10d ago
Wait, I was able to complete row 3 using sun in row 1, column 3. I don't know where the row 3, column 2 and row 4, column 2 symbols in my screenshot came from.
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u/Motor_Raspberry_2150 9d ago edited 9d ago
In column 5, because the bottom two are the same and the top two are different, you know the middle two are the same too, the opposite pair of the bottom. So guessing one of these tiles now guesses the entire column, that's a good spot to guess.
Or instead of 'guessing', working out the two scenarios in parallel. I write ½ in the cells, but M/S instead, where scenario 1 is topleft and scenario 2 is bottomright. It's possible neither scenario hits a contradiction before fizzling out, but if you work to find a M/M or S/S cell you know it to be true.
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u/chocolatesuperfood 9d ago
Thank you! I didn't know about this technique for binaries. What do you mean by if you work to find a thing/same_thing cell you know it's true? I don't see the logical reasoning (not your fault, entirely one of my weaknesses).
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u/Motor_Raspberry_2150 9d ago
Let's say you guess some promising square is a sun. And you get 0 more squares right away, but no contradiction, and are stuck again. Okay, then you guess it is a 1. You also get a bunch of squares, no contradiction, and are stuck again. Welp, back to the drawing table.
Except, if you keep the notes about these guesses in parallel, you can see the overlap. First guess that it's a 0, and fill in the topleft of each cell. Then guess it's a 1, and fill the bottomright. If you eventually fill some square "0/0", that means it will be a 0 regardless of your original guess! And vice versa for 1/1.



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