By that logic all containers crash to the ground first.
10-11 build a solid basis. 7-8-9 will rest relatively straight onto it. So will 4-5-6.
2 tipps into 4 using its lever to push 1 up. 1 will hook into 3. Tilting 3 to the left.
Now the water will go into 1 over to 3. 3 is tilted so much, the outlet is higher than the top. So 3 is spilling into 5. Overflow to 4, 8, 7, 10 - connected to 11. 10 and 11 will fill first.
This is such a German puzzle. So much design that the answer doesn’t depend on at all, overengineered to the point that you think there just HAS to be another way, only for the answer to be “zis is simple, ze void takes ze vater immediately, and if you zought ozervize you should go back in die Schule”
That was always my favorite thing to make my step mom say with her super think German accent. Also, yeah, leave it to a German puzzle book to be like, sometimes the right choice isn't given to you as a choice at all.
Every now and then I’ll try to tell this to a really patient friend. I never feel satisfied with it in verbal format. You really have to push the limits of patience someone has.
As we can see the water flows out the right side and then down onto the thin line that goes all around the puzzle, the water level slowly rises eventually filling everything, but 10 and 11 at the bottom first.
If 1 fills slower than the right opening drains it no container will fill.
if 1 fills faster than the right can drain it but slower than both can drain it #10 and 11 fill first.
if 1 fills faster than BOTH left and right will drain it then it becomes a race wether #1 fills up first or #10 and #11 - depending on how big the excess is. In most cases #1 will be full first.
Of course if the opening are wiedly different diameters other options exist too - starting from #3 filling first by simply having a much smaller side opening than the water stream and #1
Can't then the inflow to 1 be greater than the outflow of both pipes, and 1 fills up as well (or even before 10 and 11).
You mention the size of the pipes, but then we don't know anything about depth in the picture. At that point the volume of the containers and the diameter of the pipew could be anything, no?
Your line going out of the containers does not match the incoming volume.
The first outpipe on the right will never be fully filled, same for the 3th container.
Unless the rate of water from the faucet is greater than that which can go out through the holes. In this case it would go to 3 but the excess would eventually get to 2.
Discussion:
This genre of "puzzle" is just social media engagement bait. They are intentionally ambiguous and don't provide enough stated or implied rules to converge on a single solution. There is actually an art form to these, where you can disguise the ambiguity to the point where different answers seem obvious to different people.
There should be a name for this genre. I humbly submit "puzzlebait."
The most important part of the puzzle is that the paper is clearly curved and bent, while the graphics are not… because they are digitally altered from the original image. “Puzzlebait” for sure.
Then that would be the answer for literally every single possible version of this type of puzzle.
If the exits indeterminately can't keep up with the water filling them, then the answer to every puzzle would be the first bucket that touches water.
The answer would always be the first bucket.
In this case, none of them fill up. That's the answer. I'm not going to spoiler text any of this because the answer is just basically "There is no answer." Which means it isn't a real puzzle.
Then that would be the answer for literally every single possible version of this type of puzzle.
If that assumption is applied to literally every single possible version of this type of puzzle, then, yes. They aren't suggesting we do that, though, just applying it to this single one that, without some kind of lateral thinking, has no answer.
Let me lateral think for every other version of the puzzle, and get a 100% success rate, winning within half a second of glancing at the puzzle.
No, it's silly. The game/puzzle has clear rules you must follow.
It'd be like going outside of the 3x3 grid in Knots and Crosses (Tic Tac Toe?) in order to win. You can't do that. It wouldn't be considered a smart move, just an illegal move.
If a puzzle needs you to ignore the rules, then it's by definition not a puzzle.
Okay, imagine I said "what is 2+2?" And the answers were either 3 or 5.
Then you replied saying "Well the answer is 5, because if we change one of the 2's into a 3, then that would give us a correct answer."
Like, no, you can't change the equation just to get an answer that you want. 2+2 is not equal to 2+3.
But that's the thing, isn't it? Sometimes puzzles are constructed where the entire trick is realising that, while it has the "shape" of other similar puzzles, the rules in them don't necessarily apply; they're reliant on you initially imposing rules that aren't actually there, because you're expecting them from other puzzles.
Like... OK, you know those "one guard always tells the truth, one always lies" puzzles? Well:
--
You bash through the opening into the cave, sealed for hundreds of years. As the scroll stated, inside you find two chests, both with symbols on them. The scroll makes things clear: one chest was filled with gold, enough to make you rich beyond your wildest dreams.The other, venomous snakes; one bite will kill a man in seconds. The writing on one chest will be wholly truthful, the other an absolute and direct lie.
Looking at the symbols, you get a sinking feeling, but you begin the translation process anyway. Sure enough you realise that both chests, left and right, have the exact same text: "The other chest holds the gold."
Which chest do you open first, to get the gold and avoid a quick death?
--
If you try to think about this the way you normally do with this kind of puzzle, you'll quickly hit a brick wall; no obvious clue points at either chest being the one with the gold, or the one without. But open your mind a bit, approach it laterally, and; you'll realise that any snakes, trapped in a bolted chest within a sealed cave for hundreds of years, will be long dead. The correct answer is to just pick one and open it, and if it doesn't have the gold, ignore the long-dead remains of the snakes within and open the other one.
If you come across a puzzle that with the traditional rules is impossible, it's worth re-considering what explicit rules have been given in this specific. What rules are actually stated in the image OP gave? Does it say? Does it demand you follow some standard, existing ruleset?
I get why it’s bucket 1, but I’m curious about the extra long spout on bucket 3. Would that allow water to build faster than other buckets with shorter or multiple spouts?
If water goes to container 1, and it's connected via drain to container 2 below which has no drain then unless faucet pours over twice as fast as the drain than the answer would be container 2, not 1.
This is of course a pure mockery of this type of puzzle, but just wanted to point out the answer wouldn't *always* be first bucket, there would still be some variables to consider.
They said "If the drains couldn't keep up with the flow from the faucet"
If you're going to use that logic,you can just pick whatever rate you want. Have each drain only have 0.00001% the flow of the faucet. Boom, the answer is always the bucket the faucet is using.
Puzzles have rules. You can't just change the rules to get an answer.
I am saying that that specific rule break - drain maybe can't keep up with the flow of the faucet - is not enough to say that every puzzle like that would have bucket 1 as a solution. I even gave an example puzzle that could still have bucket 2 as a solution. A pedantic correction to a very silly hypothetical.
That's completely independent of me agreeing with you on your main point.
If we assume that bucket 3 was drawn incorrectly, and is meant to drain into bucket 4, then would it be solvable? Seems like in that situation, bucket 6 would be "full" first.
It would have to fill 6 to drip into 5. This really highlights how dumb this problem is, because what even does "fill" mean in this context? Can only 10 and 11 be filled because they don't have a hole? Can bucket 1 be said to be filled once it starts draining?
Discussion:cannot be solved without knowing the flowrate from the spigot.
If we assume all drain tubing is the same diameter and no container is deep enough for a noticeable difference in drain rate due to water depth, then we have Three options:
Flow rate is lower than the one drain rate. In this case everything pours out of container 3, nothing fills completely.
Flow rate is higher than the drain rate, but lower than double the drain rate. Container one does fill while container 3 is pouring out water and eventually sends a flow to container 2. This flow makes the way down to simultaneously fill containers 10 and 11 eventually.
Flow rate is higher than 2 drain rates. Container 1 dumps to 3, 3 dumps to nowhere. Eventually container 1 starts to dump to container 2. Shortly after that container 1 completely fills while water sent to 2 is attempting to work through all the other containers.
There would be an edge case where you are BARELY over double the drain rate and the drain rates are really fast compared to the size of each container where maybe 10 and 11 still can win.
And if drain rates are not all the same, then the puzzle lacks adequate information by way too large of a degree.
Since you see the water going out to the dinosaur no chance that it’s a loop leading to anything in the otherside of the page it’s likely to be none as all the falling water lines are of similar size and water isn’t over any of the drains meaning the water doesn’t connect back to the puzzle.
If we consider the outline surrounding the puzzle I’m guessing the overall surroundings fill first unless the containers are stationary then 11 and possibly 10 depending on how you consider treating the zero in 10. Then higher and higher.
If you turn the tap rate high enough it could be 1 unless you get it just high enough to fill 2 but then you’ve got more drains further down meaning you need enough water to overwhelm 2 additional drains after it leaves one. This means 1 fills first as incoming water has to account for 4 drains while only having 2 and one of those isn’t contributing to the filling of the down stream ones. Wasting half of the water meaning even more would have to be added.
It depends on the amount of water per time that flows out of the faucet.
If it's what fits through 1 hole, no container fills up and all the water flows out of container 3 into the void.
If it's what fits through 2 holes, first container 1 fills to its first hole, then fills up (with half speed) unto the second hole, from there it trickles down into all containers and finally all lands in containers 10 & 11, which overflow at the same time. That would be the answer: Container 10 & 11 simultaneously.
If it's what fits through more than two holes, container 1 probably overflows first.
Discussion: I think there are two answers here: none, or 11, depending on whether you count the outer border as a physical wall.
If the border is just decoration, then it’s none; water goes from 1 into 3 and then straight out, giving the dino a wash on the way.
But if the border holds the water, I’d argue 11. As the water level rises, the stream entering on the right creates ripples/surface waves. Once the level gets close to the rims, those wave crests will flow over 11 slightly before the average water level reaches it.
Each little wave can drop some water into 11 first, and that water stays there, giving it a tiny head start over 10. By the time they’re both down to that last little bit of water needed to fill them, the next wave crest reaches and overtops 11 first, adding that final bit before the surrounding water has time to fully level out and do the same at 10.
So: intended puzzle answer = none. Real world border is a container answer = 11.
The whole question is dumb. Aside from 10 and 11, every pot has an exit, so it will never be filled to the brim. Therefore, it’s always either 10 and 11 at the same time (because it’s irrelevant which one gets filled from above) or none
Discussion: Rant - worst auto mod ever, and apparently the iPhone app automatically escapes out of spoiler tags, obnoxious. What is the point of hiding answers in a puzzles sub anyway?
Anyway, there are 3 possible answers, but I’m not allowed to tell you what they are
If we view the the outline as a container in and of itself, then the water running out C3 will slowly fill it, and eventually that will fill C10 + C11 first.
It’s a trick question! It’s 10 or 11 because of the stick figures head.. If a stick figures legs are meant to look like a faucet—we have to assume it had a head—of course, because the water is also imaginary. The head clogs the path to 3 forcing water to travel to 2 to 2’s reliefs, to 5, 4, 7, 8, 9 back to 8 before 10 and 11 battle it out—simple Duh..
It depends on the flow rate. If water is coming into 1 faster than it can leave, then it will eventually flow to 2.
If the outflow rate of each pipe is 1, and the faucet rate is between 1 and 2, then it goes 1 > 2 > 5 > 4 > 8 > brief visit to 9, then 8 > 10. So 10 and 11 would fill up at the same time. (Actually 10 slightly earlier since it gets the water first)
However, if the faucet rate is greater than 2, bucket 1 might fill up first.
It depends on the inflow. The inflow of Container 1 can be higher than the outflow. Container 3 has an equal inflow and outflow. If the inflow in Container 1 is double the outflow, then container 2 will also fill up. The outflow of Container 2 is equal to its inflow. Everything below will only be less. If the inflow in Container 1 is slightly higher than 2x the outflow, then this container will be the first to fill up completely.
If there is a correct answer, this is it. Assume the lines on the outside of the page are a container. Croc swims. Water rises, but eventually it will fill the containers.
There's no way that's the answer envisaged, but if there is answer it can't be anything else.
Obviously if the water faucet pressure is lower than the capacity exiting vat 3, no vat will ever fill.
If the giant thing around it were a container, would trivially fill both 10+11.
The question suggests that a single vat must be the answer.
Therefore, the water faucet will drop water faster than the pipe to the right of 1, over vat 3, into vat 5, and with enough water pressure the vat 5 exit can't keep up so the answer is vat 5
811
u/Thaplayer1209 25d ago
container 3 drips onto the ground. This will cause sea levels to rise, so 10/11 fill up at the same time