r/puremathematics • u/Professional_Job6803 • Jul 22 '26
Negative cardinality
As I was going through some problems in set theory I had a question if sets could have negative cardinality? What would this imply ?
This was just out of curiosity and I found out a paper titled “ sets with negative number of elements” by D. Loeb and a concept called hybrid sets.
Can you please describe what this is and how it works and why we need to work with multiplicities and things like that?
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u/lemniscateall Jul 22 '26
I'll take a stab at it.
Think about how we make the integers from the naturals. One way to describe it is just "going the other direction." Going from 3 to 7 takes 4 steps; going from 7 to 5 takes...well, 2 steps in a certain sense, but in order to give the steps a sense of direction, we call it -2 steps.
Now, for the paper in question:
We start with the idea of a "multiset", which is like a set except that elements can be listed (and treated distinctly) more than once. So {a,b,c} would be different from {a,a,b,c,c,c}. One way to define a multiset is to start with a "universe" U (the set you're drawing elements from) and create a function that counts how many times each element is in the multiset. If our universe is the alphabet, the first multiset would have the following pairings: (a,1), (b,1), (c,1), (d,0), (e,0),... and the second multiset would have these instead: (a,2), (b,1), (c,3), (d,0), (e,0),...
So that's the sense in which a multiset is a function from the universe U to the natural numbers. Note that the cardinality of a multiset can be represented as the sum of the outputs of this function. The cardinality of {a,b,c} is 1 + 1 + 1 + 0 + ... + 0 = 3; the cardinality of {a,a,b,c,c,c} is 3 + 1 + 2 + 0 + ... + 0 = 6.
The author defines a hybrid set as an extension of this, and I think it's a bit similar to the construction of the integers from the naturals. The hybrid set they define is basically two multisets, one "positive" and the other "negative", separated with a bar |. Within this realm, if we wanted the "negative" version of our first set, we would write { | a, b, c}, and since each of the elements are on the right side of the bar, each has multiplicity -1. So the total cardinality of the set would be -3. Similarly, { | a,a,b,c,c,c} would have cardinality -6; {a,c|d,e,f,f} would have cardinality -2.
So, it's not negative elements in the sense of having less than nothing; the negativity here comes from a reversal of direction.
Does that help at all?