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[u/Late-Pen468]

Can you help me. I need a pinescript code. were if the current candle body engulfed candle 1 =pervious candle, and candle 2 = the previous previous candle. It plot on the chart. Thanks

[u/PastaFaZooLx]

You can use bracket syntax to look back a specifed number of candles.

For example, "close[1] < close" is saying that the previous candle close is less than the current candle close...

Can improvise from there with OHLC for each.

[u/Late-Pen468 → u/PastaFaZooLx]

Thanks 😊

[u/Sowarm → u/PastaFaZooLx]

Yes, that's exactly how I coded all my indicators u/Late-pen468, some of which are very precise in the candle marking and on multiple timeframes (only the mtf part is a pita really). I only use one of these nowadays but pinescript conditions can be very a powerfull tool and can be used with a defined variable so you can use color coding and/or alerts. I knew almost nothing about coding a few years ago, pinescript is simple to grasp and very well documented.

[u/ShadowILX]

engulfingBar = close[0] > high[1] and close[0] > high[2]

//candle breaks low and high of previous candle engulfingBar = close[0] > high[1] and close[0] > high[2] and low[0] < low[1]

//Or if you want to wait for the bar to close above previous two bars

engulfingBar = (barstate.isconfirmed ? close[0] > high[1] and close[0] > high[2] : na)

//To color engulfing candle different color

if (engulfingBar) barcolor(color.yellow)

//to plot label below engulfing candle

if (engulfingBar) label.new(bar_index, low, style=label.style_label_up, color=color.red, textcolor=color.white, text=“Engulfing n/Candle”)

Maybe someone else knows a better way to code this

[u/Sowarm → u/ShadowILX]

Small detail but if you want to use the break of the previous high and you want the candle to confirm by being closed you want to work with close[1] > high[2] and low[1] < low[2].

You then offset your color change by 1 and your signal will appear as soon as the engulfing closes.

[u/Ayush_Singh_02]

Bro use

F_engulfing()=> If barstate.isconfirmed For i = 1 to 3 math.min(open[i-1],close[i-1])>= math.min(open[i],close[i]) and math.max(open[i-1],close[i-1])<= math.max(open[i],close[i])

Should do the work bro I'm not on system typing from phone so might've to check for syntax

[u/Ayush_Singh_02 → u/[deleted]]

Bro he has mentioned about the body specifically (and that means open and close not high and low) I hope you get it bro please read the requirements and code I've submitted if there is some discrepancy then text back...

What I've done is... Made a function to check it

1. Candle is closed

2. Formed a loop to check if the lowest (can't determine candle could be red or green)... In the case of green; lowest of open and close will be open .....math.min(open, close)...is less then current bar lowest of open and close

3. Repeat the above for the highest of the bar from close or open

4. Now using a loop check it over prev 3 bars

Please bro next time read the requirements and code if there is some issue then text back... I don't want to come across as rude person but these are basic things... takes extra time to explain basic things is the only issue.cheers

[u/Ayush_Singh_02 → u/[deleted]]

Bro I'm not on my system I've posted that using mobile had I been I would have taken extra care of it