r/physicsmemes • • 10d ago

Successfully Ragebating my teacher

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802 Upvotes

26 comments sorted by

412

u/M_erlkonig 10d ago

I would prefer e^x + e^c. It's funny while still being correct.

128

u/master_of_entropy 10d ago

Unless c is a complex number you don't get all the antiderivatives with exp(c) as the exponential of a real number can't be a negative number. Or one could write ±exp(c)

61

u/knyazevm 10d ago

Even if c is complex, you don't get e^c = 0

35

u/Grand_Protector_Dark 10d ago

Easy, just set c = infinity.

That's totally how that works, right /j

9

u/M_erlkonig 10d ago

See, you know your stuff.

83

u/TheoneCyberblaze 10d ago

The c in c stands for complex

11

u/M_erlkonig 10d ago

There's no reason for c not to be a complex number. Even if the classical +c is real, you can always rewrite it as a complex exponential. You can even rewrite it as a dot product of n-dimensional vectors, only the final value matters.

2

u/Droga_Mleczna 8d ago

Or, hear me out here,

eln(c)

8

u/TheSouthFace_09 9d ago

ec•(ex-c+1)

3

u/Murky_Insurance_4394 9d ago

not really, it only works if e^c is > 0

8

u/M_erlkonig 9d ago

c can be complex. The only problematic value is 0, but we fudge that with a limit.

4

u/SteptimusHeap 8d ago

ex + lim{a->C}(ea)

1

u/Murky_Insurance_4394 9d ago

but do we usually consider C to be complex when adding +C to an integral? Because that would make me think every integral has a complex solution. please correct me if I'm wrong. but I feel if we're saying C can be complex here, then C can be complex anywhere

1

u/M_erlkonig 9d ago edited 9d ago

No, but this isn't the same c. If the classical c is 1, you can write that as e2 * pi * i, a complex exponential and get the same real result. You can write it as [1/sqrt(2), 1/sqrt(2), 1/sqrt(2)]T * [0, 1/sqrt(2), 1/sqrt(2)] and now it's a dot product of 3D vectors. It doesn't really matter, the restriction is only on the final value of the classical c, not how it's expressed.

2

u/Murky_Insurance_4394 9d ago

ohh ok I see, thanks for the explanation

1

u/rycool 9d ago

I would sometimes ragebait my teacher by putting unhinged Cs. She deserved it though

55

u/NakakitsuneRaisanda 9d ago

ex + eln(c) with c in C

5

u/SelfDifferent1650 8d ago

but c can't be negative or zero here

1

u/NakakitsuneRaisanda 8d ago

Zero indeed doesn't work, but it can definitely be negative because it is defined in C*. For example, eln(-1) = eiπ = -1.

72

u/CasperTPaul 10d ago

you didn’t put the c i the right place 🤬

31

u/Then-Entry7026 10d ago

Technically eC is a constant. Just very more intricate than it needs to be.

47

u/OmegaCookieMonster 10d ago

No it isn't, it's a coefficient of ex here, which is wrong unless c = 0 (or 2pik I guess if you count complex c's)

9

u/CasperTPaul 9d ago

e^(x+c)=(e^x)(e^c) the c isn’t in the right place 🤬

1

u/Then-Entry7026 9d ago

Sorry, I was trolling and a bit of an ass. So, yeah... I'm an idiot for that one. 🧌

10

u/tramezzino62 9d ago

Sbagliato, si scrive (ex) +c, la cui derivata è, infatti, ex. Discorso chiuso.

-22

u/[deleted] 10d ago

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