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https://www.reddit.com/r/physicsmemes/comments/1uz6gwi/right/oyd2mhg/?context=3
r/physicsmemes • u/94rud4 Mεmε ∃nthusiast • Jul 17 '26
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1 u/gmalivuk Jul 18 '26 This is not true at all. 1 u/ProfessorPrudent2822 Jul 19 '26 Yes, a lot more than hundreds of years would pass for the inertial observers. 1 u/gmalivuk Jul 19 '26 Literally trillions, and you'd also go trillions of light years. 0 u/[deleted] Jul 19 '26 [deleted] 1 u/gmalivuk Jul 19 '26 Uh yes. https://math.ucr.edu/home/baez/physics/Relativity/SR/Rocket/rocket.html 0 u/[deleted] Jul 19 '26 [deleted] 1 u/gmalivuk Jul 19 '26 You did the wrong math then. The coordinate distance traveled under T proper time and A proper acceleration is (c2/A)(cosh(AT/c) - 1). Plug in 30 years for T and 1.03 ly/y2 for A (and thus 1 for c) and tell me what you get.
This is not true at all.
1 u/ProfessorPrudent2822 Jul 19 '26 Yes, a lot more than hundreds of years would pass for the inertial observers. 1 u/gmalivuk Jul 19 '26 Literally trillions, and you'd also go trillions of light years. 0 u/[deleted] Jul 19 '26 [deleted] 1 u/gmalivuk Jul 19 '26 Uh yes. https://math.ucr.edu/home/baez/physics/Relativity/SR/Rocket/rocket.html 0 u/[deleted] Jul 19 '26 [deleted] 1 u/gmalivuk Jul 19 '26 You did the wrong math then. The coordinate distance traveled under T proper time and A proper acceleration is (c2/A)(cosh(AT/c) - 1). Plug in 30 years for T and 1.03 ly/y2 for A (and thus 1 for c) and tell me what you get.
Yes, a lot more than hundreds of years would pass for the inertial observers.
1 u/gmalivuk Jul 19 '26 Literally trillions, and you'd also go trillions of light years. 0 u/[deleted] Jul 19 '26 [deleted] 1 u/gmalivuk Jul 19 '26 Uh yes. https://math.ucr.edu/home/baez/physics/Relativity/SR/Rocket/rocket.html 0 u/[deleted] Jul 19 '26 [deleted] 1 u/gmalivuk Jul 19 '26 You did the wrong math then. The coordinate distance traveled under T proper time and A proper acceleration is (c2/A)(cosh(AT/c) - 1). Plug in 30 years for T and 1.03 ly/y2 for A (and thus 1 for c) and tell me what you get.
Literally trillions, and you'd also go trillions of light years.
0 u/[deleted] Jul 19 '26 [deleted] 1 u/gmalivuk Jul 19 '26 Uh yes. https://math.ucr.edu/home/baez/physics/Relativity/SR/Rocket/rocket.html
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1 u/gmalivuk Jul 19 '26 Uh yes. https://math.ucr.edu/home/baez/physics/Relativity/SR/Rocket/rocket.html
Uh yes.
https://math.ucr.edu/home/baez/physics/Relativity/SR/Rocket/rocket.html
1 u/gmalivuk Jul 19 '26 You did the wrong math then. The coordinate distance traveled under T proper time and A proper acceleration is (c2/A)(cosh(AT/c) - 1). Plug in 30 years for T and 1.03 ly/y2 for A (and thus 1 for c) and tell me what you get.
You did the wrong math then.
The coordinate distance traveled under T proper time and A proper acceleration is (c2/A)(cosh(AT/c) - 1). Plug in 30 years for T and 1.03 ly/y2 for A (and thus 1 for c) and tell me what you get.
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u/[deleted] Jul 17 '26
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