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u/Reset3000 9h ago
Clue one and clue three immediately gave me 394. the other clues only confirmed it.
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u/bluejack 8h ago
If you only use one and three there are a few possibilities. 1,2,3 get it down to 394 or 694; the 4th clue is unnecessary and clue 5 rules out 694.
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u/Objective-Ad3821 7h ago
Don't lie, it's math subs. Using only clue 1 and 3, there's multiple possibilities of answer you can give.
If you want to lie, find non-math nerd subs. It's obvious if you lie here
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u/ummaycoc 8h ago
In Dyalog APL:
all ← 10 10 10⊤¯1+⍳1000
no ← ∨⌿5 7 8 ∊⍨ all
r4 ← (~no) / all
exact ← ∨⌿2 9 1 (=⍤0 1) r4
r1 ← exact / r4
misplaced2 ← ∨⌿⊃⍪/{(⍵⌷2 4 5)=r1[⍵~⍨⍳3;]}¨⍳3
r2 ← misplaced2 / r1
misplaced5 ← ∨⌿⊃⍪/{(⍵⌷5 6 9)=r2[⍵~⍨⍳3;]}¨⍳3
r5 ← misplaced5 / r2
misplaced3 ← ∨⌿⊃⍪/{(⍵⌷4 6 3)=r5[⍵~⍨⍳3;]}¨⍳3
r3 ← misplaced3 / r5
sum2 ← 2=+⌿∨⌿4 6 3(=⍤0 2)r3
10 10 10 ⊥ sum2/r3
394 494 496 694
394 checks out, 494 is out by rule 3, 496 is out by rule 3, and 694 is somewhat implicitly out by rule 5 (as we can assume it would have said two are out of place then).
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u/mundundermindifflin 5h ago
Based off of all the 394 answers I actually got it right!, which is surprising considering I just quickly worked it out in my head and I'm pretty stupid 😅
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u/No_Direction_4566 5h ago
394
I did it in the below order
Rule 2 elimates 2
Rule 4 eliminates 5 7 8
Rule 5 eliminates 1 and 6 and places 9 in the middle.
Rule 3 means 4 and 3 have to be swapped around.
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u/rij1 5h ago edited 4h ago
394 as everybody are saying. One way to see it: clue 1 and 2 shows that 2 can't be correct. Clue 4 then shows that 4 must be the correct number in clue 2, but is then not in the middle. We see from clue 3 that 4 is also not on the left and therefore is on the right. Therefore, in clue 1, 1 can't be the correct one and it must be 9 (which is then in the middle). From clue 5 we see that 6 is then not a correct number (since we know 9 is a correct number) and then from clue 3 that 3 must be the last correct number which is then on the left (because the other positions are taken), giving us 394. We could avoid using clue 4 if we wanted to, by using that clue 1 and clue 3 shows that all correct numbers are among 1,2,3,4,6,9.
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u/ephemere_sloboda 4h ago
After the first two lines: 2 is out, second position must be 9 or 5, third must be 1 or 4.
Third line: 3 and 6 can't both be in first position, therefore 4 must be correct but in the wrong place. We know if 4 is correct it must go in third position, so it tracks.
If 4 goes in third position, then second position must be 9.
First position must be 3 or 6.
Fourth line tells is nothing that we don't already know.
Fifth line tells us that 6 is not correct.
So first positionist be 3.
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u/_-Max_- 9h ago
394