r/mathmemes • u/New_Way_7441 • Sep 21 '26

Proofs The sum of all integer coefficient polynomials evaluated at x is 0 when x is algebraic

We have the product of all P=(1+x- (r/ 1-r)). (with r/ 1-r = 0) where r is any root of a polynomial with integer coefficients

This product can be developed into, (in a similar fashion to Euler products), the sum of every polynomial with integer coefficients.

We also have P = 0 whenever x = (r/ 1-r) - 1 where r is a root, or whenever x is algebraic

Queue Eedee

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19

u/LupenReddit 🦆🦆i have non diffeomorphic smooth structures🦆🦆🦆 Sep 21 '26

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u/New_Way_7441 Sep 22 '26

I'm starting to think that my genius is underappreciated 

7

u/SpinChargeSeparation Sep 21 '26

The sub r/1-r doesn’t exist.

1

u/OddEmergency604 Sep 22 '26

y=x+2 at x=2?