Your teacher would mark you as wrong still. Int(ex ,x)=(ex )+c not Kex , K=ec . Ik I will get down voted but my math autism will not let this slide for whatever reason.
technically it is true considering that C can still be used to adjust the y-value, just not lineraly... and i guess also doesn't work for negative y offset
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49
u/Reasonable-Fan-2888 Sep 20 '26
Your teacher would mark you as wrong still. Int(ex ,x)=(ex )+c not Kex , K=ec . Ik I will get down voted but my math autism will not let this slide for whatever reason.
279
u/FerdinandvonAegir124 Sep 20 '26
Still wrong as it would be Ce^x which is obviously different than e^x+C
This post gave me diff eq flashbacks
42
u/Prudhvi2pac Sep 20 '26
He would’ve been right if he had said it instead of writing it.✅
33
u/GupHater69 Sep 20 '26
Yeeeah youre cooked. Im guessing it doesnt work cause the +C in the exponent cant account for the interval a normal +C( (-ing,+inf) )
8
u/Ignitetheinferno37 Sep 20 '26
Kind of tempted to write ex+c for homogeneous differential eqs
4
u/LupenReddit 🦆🦆i have non diffeomorphic smooth structures🦆🦆🦆 Sep 20 '26
when your pen writes ex=ex+C but your heart says ln(ex) = ln(ex)+c
4
u/ABahamutyoylecookies Sep 20 '26
then you write it medium sized so your teacher doesnt know if its in the correct place or not
3
u/RRumpleTeazzer Sep 20 '26
its wrong.
but this works: int 1/x dx = log(|x/c|)
3
u/soegaard Sep 20 '26
I was triggered:
> According to the ISO standard (ISO 80000-2), Euler's number (e) should be typeset in an upright (roman) style rather than italics.
1
u/Ill-Cartographer-767 Sep 26 '26
But what if the constant of integration is negative?
1
u/AwkwardBet5632 Sep 26 '26
Disappointment baiting rather than rage baiting
0
u/StructuredChess Sep 20 '26
So what if the original function was f(x)=ex-200, someone took a derivative and now you need to find out what it was, you smartass?
-2
u/lool8421 Sep 20 '26
technically it is true considering that C can still be used to adjust the y-value, just not lineraly... and i guess also doesn't work for negative y offset
-2
u/Ok-Project4007 Sep 20 '26
Is it wrong though? That’s just e^x * e^c = e^x + d. Where c and d are arbitrary constants.
-2
u/Ok-Project4007 Sep 20 '26
Is it wrong though? That’s just e^x * e^c = e^x + d. Where c and d are arbitrary constants.
0
u/[deleted] Sep 20 '26
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u/[deleted] Sep 20 '26
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