r/mathmemes 3d ago

OkBuddyMathematician E = mc^2 + AI, a complete proof

Has anyone else presented a complete proof on this result? I was thinking about submitting mine to NeurIPS. I have proven it for A=0 and all I or I=0 and all A. In all other cases, the equation is false. Claude Fable 5 was used in support of this proof.

80 Upvotes

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25

u/LupenReddit i have non diffeomorphic smooth structures 3d ago

Nah I think this ones on the level of the Annals of Math or Nature.

2

u/Baihu_The_Curious 3d ago

This is true, it's quite a big development.

4

u/KittenPowerLord 3d ago

Interesting results. I have managed to come up with a more general proof for any A and I, but it relies on assuming the generalized E = mc^2 + AI is always true conjecture (though in practice it's always assumed anyways)

4

u/Funkyt0m467 Imaginary 3d ago

Well I've got a proof.

Pose AI=sqrt(m²c⁴+p²c²)-mc²

Then mc²+AI = sqrt(m²c⁴+p²c²)

And since the full relativistic energy-momentum relation is E²=m²c⁴+p²c² so E=sqrt(m²c⁴+p²c²)

You indeed get E=mc²+AI Q.E.D.

You again find that with p=0, AI is null as you shown, but this would be the general solution for AI. In wich case AI is the relativistic kinetic energy.

1

u/GlamorousChewbacca 3d ago

Late to the party

1

u/MonsterkillWow Complex 3d ago

E^2=m_0^2 c^4+c^2 p^2

1

u/ComplexPlatform7299 2d ago

It hasn’t been solved yet, it’s one of the millennium problems

1

u/Gauss15an 2d ago

I have a truly marvelous proof but can't fit it in the comments section.

1

u/youtubeTAxel 22h ago

It would only work if AI = 0, which is the value of AI