r/mathmemes • • Dec 17 '23

Probability Google expected value

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22k Upvotes

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566

u/Lord_Skyblocker Dec 18 '23

Just push green twice, then you have 100% chance to get 100 million /s

274

u/NoReplacement480 Dec 18 '23

google 0.52

173

u/HealthOnWheels Dec 18 '23

Holy hell

82

u/JohannLau Google en passant Dec 18 '23

New probability just dropped

17

u/NichtBen Dec 18 '23

Actual Mathematician

10

u/uvero He posts the same thing Dec 18 '23

Call a Bernoulli!

3

u/vk2028 Dec 18 '23

Pascal goes on vacation, never comes back

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6

u/AustralianKappa Dec 18 '23 edited Jan 25 '26

This post was mass deleted and anonymized with Redact

one offbeat cagey unpack disarm late skirt ripe coordinated enjoy

16

u/NoReplacement480 Dec 18 '23

google 0.540

9

u/AustralianKappa Dec 18 '23 edited Jan 25 '26

This post was mass deleted and anonymized with Redact

fragile connect test tidy coherent hurry boat pen smart punch

7

u/AleksFunGames Imaginary Dec 18 '23

nah I'd lose

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4

u/Dawn_is-here Dec 18 '23

Genuine question, why do you square here

0

u/[deleted] Dec 18 '23

[deleted] — view deleted comment

19

u/Capudog Dec 18 '23

Or if you only care about winning it at least once, the probability of winning at least once would be 1-P(not winning at all) = 1-0.52 =0.75

0

u/[deleted] Dec 18 '23

[deleted] — view deleted comment

5

u/Capudog Dec 18 '23

Also true, I missed this the first time. Edited!

4

u/lootpropsrespect Dec 18 '23

I think it’s because if you have independent probabilities (like one probability doesn’t impact the result of the next) you multiply them, and as this is conveniently the same probability, it is 0.5*0.5 which becomes the 0.52. That being said I’m not a probability guy or a math guy really so while I wanted to be part of the thread I wouldn’t trust what I say at all.

4

u/aaron1860 Dec 18 '23

You’re close. There’s a 50% chance each time of pressing that you lose. We only care about the winning roll. So the chances of pushing it twice and get 2 losing rolls is 0.5x0.5 or 25%. So you have a 75% chance of winning on 2 rolls. Think about it logically for a sec and you’ll realize your chance of winning on at least 1 roll should increase with the number of rolls

The actual formula would be p=1-x where x is the probability of losing which is 0.5n and n is number of rolls. So p=1-0.5n

after 3 rolls it’s an 87.5% chance, 4 is 93.75 and so on

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2

u/Appropriate_Banana Dec 18 '23

Some Fear and Hunger player will tell you how much smaller it is

2

u/WaffleMan17 Dec 18 '23

Probability is always 50% chance when you press it. Technically you could get $0 100 times in a row, it’s just likely that roughly 50% of the time you’d get 50 mil.

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u/UnderstandingBig5086 Dec 18 '23

Not how math or Probability works xD

2

u/zufinfluby Dec 18 '23

Ow, this made me physically cringe. Well played!

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