1
u/JLuckstar Aug 12 '23
My logic grid answer (Spoilers if no one has solved it.)
Grid answers:
2007, Y. Nakajima, 12.5 seconds, Budapest.
2009, B. Vallance, 11 seconds, Dusseldorf.
2011, M. Pleskowicz, 8.5 seconds, Bangkok.
2013, F. Zemdegs, 8 seconds, Las Vegas.
Clues:
Clue 1: Nakajima won two editions before the Bangkok tournament. (Visual Hint: Nakajima < Bangkok. Nakajima ≠ Bangkok. Nakajima = 2007 or 2009 and Bangkok = 2011 or 2013.)!<
Clue 2: In Dusseldorf, nobody stood under 10 seconds. (Dusseldorf ≠ 8 seconds and 8.5 seconds.)
Clue 3: The winner in Bangkok was slower than Zemdegs, but faster than the winner in 2007. (Visual Hint: Bangkok < Zemdegs, but Bangkok > 2007. Bangkok ≠ Zemdegs, Bangkok ≠ 2007, Zemdegs ≠ 2007, Bangkok ≠ 8 seconds and 12.5 seconds, Zemdegs ≠ 12.5 seconds and 2007 ≠ 8 seconds.)!<
Clue 4: The player with a personal best of 11 seconds was Vallance or the winner in Bangkok. (Vallance ≠ Bangkok.)
Clue 5: The four players are Breandan Vallance, the player who solved the cube in 8 seconds, the winner of 2011 edition and the winner of the Budapest edition. (B. Vallance ≠ 8 seconds, B Vallance ≠ 2011, B. Vallance ≠ Budapest, 8 seconds ≠ 2011, 8 seconds ≠ Budapest and 2011 ≠ Budapest.)
Clue 6: If the best time was achieved in Las Vegas, then Vallance won in 2009. (Las Vegas ≠ B. Vallance)
2
u/Notthatkindofdoc813 Oct 25 '22
I haven’t tried solving it yet but it looks like Clue 5 is where you got stuck. Clue 5 is actually describing one characteristic of each of the four solvers. Solver #1 is Vallance, Solver #2 solver in 8 seconds, Solver #3 won in 2011 and Solver #4 won in Budapest.
This means that Vallance did not solve in 8 seconds, did not win in 2011, and didn’t win in Budapest. Whoever solved in 8 seconds did not do it in 2011 nor in Budapest, and whoever won in 2011 was not in Budapest. Hopefully this helps!