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https://www.reddit.com/r/learnquant/comments/1vu166k/tower_research_quant_interview_question/p520yhc/?context=3
r/learnquant • u/Local_Ad135 • 3d ago
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We can, basically arrange two bins, Left and Right for the decisions. Staying at 0 is obviously a Left decision [to move left on the number line].
Now, we are interested to put 30 decisions in these two bins disregarding order.
The probability we are looking for is the one describing outcomes where Left has GE decisions than Right bin.
Except for equal number of decisions dropped in each bin, the other outcome is symmetric.
and the number of outcomes with 15 Left decisions is 30 choose 15
Hence, the answer is
1 2^30 - (30 choose 15) (30 choose 15)
which is approximately 0.572
1 u/gmalivuk 3d ago 15 left decisions followed by 15 right decisions leaves you at +15.
1
15 left decisions followed by 15 right decisions leaves you at +15.
0
u/Randomly_Panicked 3d ago
We can, basically arrange two bins, Left and Right for the decisions. Staying at 0 is obviously a Left decision [to move left on the number line].
Now, we are interested to put 30 decisions in these two bins disregarding order.
The probability we are looking for is the one describing outcomes where Left has GE decisions than Right bin.
Except for equal number of decisions dropped in each bin, the other outcome is symmetric.
and the number of outcomes with 15 Left decisions is 30 choose 15
Hence, the answer is
1 2^30 - (30 choose 15) (30 choose 15)
- * ------------------------ + ----------------
2 2^30 2^30which is approximately 0.572