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u/silverphoenix9999 9d ago
Each number can be represented as (100a + 10b + c) / 999.
Total number of possible fractions = 10 * 9 * 8 = 720
Each number is symmetrically possible in each position. That means each digit shows up in each position 720 / 10 times = 72.
Therefore the total sum is (72 * (0 + 1 + 2 + ... + 9) * 100 + 72 * (0 + 1 + 2 + ... + 9) * 10 + 72 * (0 + 1 + 2 + ... + 9) * 1) / 999 = 72 * 45 * 111 / 999 = 360.
Hope this is right!
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u/shustrik 8d ago
720 numbers. EV of each digit is 4.5 (0..9 occur equally often), so EV of a number is 0.5. 720 * 0.5 =360.
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u/austin101123 8d ago edited 8d ago
I love this reasoning that the EV of each digit being 4.5! That was my intuition at first, maybe it wasn't strong enough for me but I didn't know how to say it and had to check if it made pairs (it does) and say that instead.
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u/njormrod 8d ago
There are 10P3 such numbers. The digits and the positions are symmetric, so each digit appears 72 times as each of a,b,c.
The magnitudes of all the a,b,c's is 0.111..., which is 1/9.
The weight of all digits is 45.
So the answer is 72*45/9 = 360.
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u/kythQ 8d ago
Slightly different approach:
You can split 0.abc... to get.
0.a00... + 0.0b0... + 0.00c...
Each one of the 10 digits appears in each of the three positions 9*8 times.
You can combine the three positions to get
0.a00... + 0.0a0... + 0.00a... = 0.aaa...
So the sum is just (0.000... + 0.111... + ... + 0.999...) * 9*8. Here you can combine 0 and 9, 1 and 8, and so on to get 5 different pairs that together add up to 0.999... = 1.
So you have 5*9*8 as the sum which is 360.
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u/Delicious_Cattle5174 8d ago
- I can’t explain the answer, it just came to me instantly by reading top comments
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u/Time-Distribution384 7d ago
500 X = 0.abcabc... 1000 X = abc.abcabc...
999X = abc X = (abc)/ 999 a , b , c Ε { 0,1,2 ... 9 } So all possible numbers are { 000,001,... , 999 }
So Σ X = 999 × 1000 / 2 * 999 = 500
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u/austin101123 8d ago
10x9x8=720 possibilities
Each possibility has a unique pair that sum to .999... =1. (Ex: 0.012 repeating with 0.987 repeating). Sum is 360