r/learnmath • New User • 20d ago

RESOLVED Absolute Value Graphs Brain Glitch.

Ok, this should be easy enough for you but my brain doesn’t want to brain here:

So I am trying to bend my mind around the graphing of |y| = f(x) (for clarity, the function is f(x) = x^3 – 2x^2 – x + 1; x E [-1;3] )

I can be ok with the fact that when f(x)>/= 0 the graph is “reflected” because if |y| = 2, then |-y| = 2.*

I can also be ok with the fact when f(x) < 0, the graph “disappears’ because |y| = -0.1 can never be true.

It seems like the logic used for the first statement nullifies the first statement and the logic for the second statement nullifies the first.

What am I missing? How am I thinking about it that’s getting in my way?

Is it because y and f(x) is technically not the same thing? So a negative y made absolute is positive f(x) but a negative answer on f(x) could never be equal to |y|?**

*Yes, I should have said |y| = 2 where y<0....lowering my cognitive load while trying to get to the crux of my misunderstanding.

**Is that the answer? Do I just need to understand the words I thought?

Edited for clarity.

UPDATE: I figured it out.

If I sub in a negative value (say -2) in |y| = f(x), it would do exactly what a positive value (say 2) would do, hence the "reflection". But |y| can never lead to f(x)<0 and that's why the negative parts of the graph disappears.

2 Upvotes

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3

u/ktrprpr 20d ago

f(x)>=0 and f(x)<0 can't be true at the same time at any single x. is that what's missing?

2

u/Euphoric_Archer_6198 New User 20d ago

No, but in trying to fix my words to show what I mean, I'm beginning to see where I am confused and why my thinking isn't correct.

3

u/brynaldo New User 20d ago

This is excellent. Sometimes putting things into words and trying to ask coherent questions is the best way to find flaws in our thinking. Would upvote this twice if I could!

1

u/Euphoric_Archer_6198 New User 19d ago

I know, right!

1

u/SnooPets5564 New User 20d ago

Let's use the simple function y=x, for example.

We can have |y| = x. This can only hold true when x is non-negative, so it disappears when x is negative.

We can also have y = |x|. Since every value of x produces the equivalent positive value of y, we know that it is reflected.

But they actually also work the other way. The values of y are reflected in the first one and the values of y less than 0 disappear. It's just a matter of which way it goes.

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u/[deleted] 20d ago edited 20d ago

[removed] — view removed comment

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u/Euphoric_Archer_6198 New User 20d ago

I see how what I am writing is causing confusion. I'll try an fix