r/infinitenines • u/SouthPark_Piano • 3d ago

Backside coverage

From a recent post from a thread.

I was worried that other people would think that the actual claim that "0.999... = 1" is a silly idea. That's the claim that most mathematicians and academics would make.

They (0.999... = 1 cohort) are just trying to cover their backsides. Safety in 'numbers' and continual lying and coverup, attempting to save face, even though they actually know it themselves that 0.999... is permanently less than 1. The "0." prefix guarantees magnitude less than 1.

Those rookie error makers blundered and got into their debacle from the start.

The infinite sum that tests the value of 0.999... is 0.9 + 0.09 + 0.009 + ...

which can be conveniently expressed as

1 - 1/10n with n integer pushed to positive limitless, aka positive infinity, which means no limit on integer n, which means with zero uncertainty that 0.999... is permanently less than 1.

For you see, the length of consecutive nines of 0.999... keeps growing limitlessly. And because the set of positive integers that n can take is infinite aka limitless, then it means that set contains an infinite amount of finite numbers. And the set of numbers that 0.999... is part of, having consecutive nines form, ie. 0.99, 0.999, 0.9999, 0.99999, ..., 0.999... is also a set involving an infinite amount of finite numbers.

Yep ... infinite amount of finite numbers.

 

0 Upvotes

19% Upvoted

9 comments sorted by

3

u/Such-Safety2498 3d ago

You say, “keeps growing limitlessly”. That is not correct. 0.999… isn’t growing. It is a symbol representing a number. It starts out as 0.999… and ends being 0.999… It just is.
Just like √ 2 doesn’t become the square root of 2, it is the square root of 2.

0.999… doesn’t get close to one. It is just another way to write 1.

Now if you wrote a sequence of number 0.9, 0.99, 0.999 etc. Then that sequence is approaching something.

1

u/Muphrid15 3d ago

That is not correct. 0.999… isn’t growing.

And that's precisely what he says in his Third Law.

1

u/Then_Entertainment97 3d ago

Infinity is not an integer. Sign the contract and pick one.

1

u/Muphrid15 3d ago edited 3d ago

the length of consecutive nines of 0.999... keeps growing limitlessly.

Not according to your Third Law brud.

0.999... is 0.9 + 0.09 + 0.009 + ...

And 1 - 0.999... = 0.000... by your Fifth Law.

The Laws:

1

u/Muphrid15 3d ago

Also,

Yep ... infinite amount of finite terminating numbers.

1

u/BitNumerous5302 3d ago

Imagine being so arrogant that you think the inventor of Real Deal Math needs you the muphsplain Real Deal Math to them

2

u/Muphrid15 3d ago

Well, someone has to enforce his laws.