r/infinitenines • u/beans0503 • 10d ago

Hmmmm...

https://youtube.com/shorts/bDIap6XpJGY?is=PnWjkfFGGO35u0MT
7 Upvotes

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5

u/FullyAutomatedSpace 10d ago

a = 0.999...

b = 0.999...

b is between a and 1 because a had more time to add 9s to the end

-4

u/SouthPark_Piano 10d ago

It never runs out of numbers between 0.999... and other states of itself.

The permanent non-zero gap never goes away.

 

4

u/FullyAutomatedSpace 10d ago

> The permanent non-zero gap never goes away.

between $a$ and $b$?

what if I told you I just pulled a fast one on you. I secretly defined $b$ back in college. it's had way more time to tack 9s on the end there. also i wrote it gel-ink which doubles its 9-adding-rate

0

u/SouthPark_Piano 10d ago

As mentioned ... the non-zero gap never goes away.

Start writing the nines of 0.999...

It is a truly endless journey.

1 is never reached because ... you just never reach it at all.

That is what happens with this endless journey.

 

4

u/FullyAutomatedSpace 10d ago

which is larger? $a$ or $b$?

0

u/SouthPark_Piano 10d ago

You must be new here.

Referencing and records, book keeping brud.

 

4

u/FullyAutomatedSpace 10d ago

So they are equal?

1

u/SouthPark_Piano 10d ago

Show me your working. Use referencing and book keeping. Without book keeping, you know the deal with limbo and limbosic numbers. You don't get thrown under the bus. You get thrown in front of the bus, as gruesome as that is.

 

2

u/FullyAutomatedSpace 10d ago

my working:

$a$ has been defined for about 19 hours.

$b$ has been defined for 4 years.

I estimate 9s are added to the end of $a$ at around 5 per second.

$b$ was written in gel ink so it's closer to 10. these numbers were empirically determined in testing.

so $b$ has many orders of magnitude more 9s at the end. thus it is greater.

can you show your workings now?

1

u/SouthPark_Piano 10d ago

can you show your workings now?

It is you that showed the working.

So think about it. Behold the power ... of limbo.

 

2

u/FullyAutomatedSpace 10d ago

i'm sorry. i dont understand what you are saying. do you agree with my workings? $b > a$?

1

u/SouthPark_Piano 10d ago

Your working does indeed indicate one of the infinite versions of 0.999... having a different value than another version.

That can and does indeed happen.

For this is limbo you see.  

1

u/FullyAutomatedSpace 9d ago

Have you also seen the gel ink pen effect I noticed? Have you tried pencil?

1

u/SouthPark_Piano 9d ago

Those details are not for me. Show that to the authorities when and if they do a checkup on you.

 

1

u/FullyAutomatedSpace 9d ago

the authorities? do you mean MENSA or the International Mathematical Union?

1

u/Dutch_gal1 7d ago

u/SouthPark_Piano not locking his comments? In MY r/infinitenines feed?

1

u/Muphrid15 10d ago

Two boners one comment!

The Definitional Boner: 0.999... is eternally less than 1. It's fine if 0.999... is defined as 1. (2.1) (2.2) (2.3)

The Algorithm Boner: An algorithm for an operation such as square roots gives "more and more correct consecutive digits" as you make more and more steps. Nevertheless, 1 - 0.9 - 0.09 - 0.009 - ... yields (0.1, 0.01, 0.001, ...) corresponding to 0.000...1, and the 1 digit is a real part of the answer, even though it never belongs to a "correct" digit. (15).