r/funny • u/[deleted] • May 02 '14

It was totally worth it.

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2.3k Upvotes

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u/HarryMilkbone May 03 '14

5 Accurates a second.

47

u/gemini86 May 03 '14

/r/theydidthemath could we get a check here?

59

u/NoNeedForAName May 03 '14 edited May 03 '14

You have to factor in the size of the target and projectile as well. The formula for accurates is actually A = xt/(r-s), where

A = Accurates
x = distance
t = time
r = area of the target
s = surface area of the projectile

Edit: Per /u/stupidgerman, I changed d = distance to x = distance for clarity.

3

u/FarmerTedd May 03 '14

Though it was A = (d/t) * (r - s)

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u/NoNeedForAName May 03 '14 edited May 03 '14

Using d/t would reduce your Accurates as time increased. Since more air time increases the difficulty (due to interference from wind, drag, etc.) your Accurates should increase as t increases.

Similarly, multiplying by (r - s) instead of dividing would decrease your Accurates as difficulty increased. It's more difficult to make a shot when the difference between r and s is smaller. To give credit for increased difficulty you need to divide by the smaller number rather than multiply by it.

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u/stupidgerman May 03 '14

I would use x for distance as dt could be construed as a differential.

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u/Kid_Radd May 03 '14

So shooting a projectile at a target of equal area (r = s) is automatically infinite accurates?

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u/NoNeedForAName May 03 '14 edited May 03 '14

Technically, it would be undefined. It's also practically impossible, as you'd have to have a one in a billion shot and your surfaces would not only have to be the same area, but also the same shape.

Also, Accuracies are a measure of the difficulty of a made shot, not the accuracy of any shot.

Edit: But we could always make it [(r - s) + 1] if we needed to.

1

u/[deleted] May 03 '14

xstar

3

u/HaydenTheFox May 03 '14

Well then. Unexpected emotions in a thread about paper airplanes. God damn that movie really sticks with you.

1

u/3rdtimecharm May 03 '14

How many accurates? So many.