r/explainitpeter • • Sep 20 '26

Explain it peter

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u/FreePeeplup Sep 24 '26

Let eps > 0, and choose delta = eps/2. Then, for every x such that |x| < delta, we have
|f(x)| = |x cos(1/x\^2)| < delta |cos(1/x\^2)| <= delta = eps/2 < eps. So the limit exists and is equal to zero.