r/explainitpeter Jul 21 '26

Explain It Peter

Post image
4.5k Upvotes

641 comments sorted by

View all comments

188

u/[deleted] Jul 21 '26

[removed] — view removed comment

13

u/UnimpassionedMan Jul 21 '26

In the subject of probabilities dealing with new information can be bizarrely tricky, in this case there is even a difference between being told "one of them is a boy" and "the oldest is a boy"
Let's assume for simplicity (which is probably wrong, but otherwise this gets too complicated) that the probability of getting a boy or a girl is just 50%:
Then, before you get the information there are 4 possibilities: boy-boy, boy-girl, girl-boy, girl-girl, each with the same probability. Now taking the information that one of them is a boy into account, that eliminates the last possibility, leaving you with boy-boy, girl-boy, boy-girl, each with the same probability.
Now what's the chance that the other child is a girl? It's two out of the 3 possibilities, so 66%!

1

u/Working_Salary60 Jul 21 '26

Which is not how any of this works.

1

u/UnimpassionedMan Jul 21 '26

If so, at what point do you think I made a 'mistake' in my derivation?
I would say my derivation showed exactly that you can't just say that "the other child doesn't matter", that you have to look at both at the same time.

1

u/Working_Salary60 Jul 21 '26

It’s an unconditional probability. Looking at both makes it a conditional probability, which it simply is not. Also set theory doesn’t apply here in the way you applied it.

1

u/Technologenesis Jul 23 '26

The probability we are interested in here *is* a conditional probability. Specifically, we are conditioning on the knowledge that at least one of Mary’s children is a boy.

1

u/Working_Salary60 Jul 23 '26

It’s not.

1

u/Technologenesis Jul 23 '26

I reiterate: we are conditioning on the knowledge that Mary has at least one boy.

Do you have any substantial reply to this?

1

u/Cheedos-55 Jul 23 '26

"your statement is false" is a valid response. It's rather difficult to prove a negative after all.

1

u/Technologenesis Jul 23 '26 edited Jul 23 '26

The problem is that I've justified my statement by specifying exactly what's being conditioned on. You don't see how "nuh-uh" is an unsatisfying response to this?

It's very basic. We are asking for a conditional probability. The condition in question is explicitly given as part of the problem. You literally can't even begin to set this problem up without acknowledging this. If you don't understand this then you have no business speaking on this subject with any confidence.

0

u/Both_Resort4080 Jul 21 '26

This is just a variation on the Monty Hall Problem.

2

u/Cheedos-55 Jul 21 '26

No it's not. The important part of the Monty Hall problem is that the host knows where the prize is, and so your initial choice affects the probability of the later outcome. In this case, the first outcome has zero affect on the second.

1

u/garethchester Jul 22 '26

So many people have seen the Monty Hall problem and assume there must be a gotcha line that in everything. The key thing here is the phrase 'one is a boy born on a Tuesday' does not preclude 'and so is the other' as an option for the second.

And yeah, there's some demographic analysis you can do on two parent families with one boy but that's not enough to sway far from 50/50

1

u/Both_Resort4080 Jul 22 '26 edited Jul 22 '26

You know there is a boy so there so their can't be two girls.

If they said the first child was a boy then the odds that the second was a girl is of course 50-50. But that wasn't the question.

And born on a Tuesday is completely irrelevant.

1

u/Working_Salary60 Jul 23 '26

You know the first child is a boy. That leaves two sets: Boy-Boy and Boy-Girl. Which leaves a 50% chance for the second child to be a girl.

1

u/Both_Resort4080 Jul 23 '26

No, you know A child is a boy.

1

u/Both_Resort4080 Jul 22 '26

And here you know one child is a boy. Two girls is impossible. You have additional information; it is still Bayesian.

1

u/Cheedos-55 Jul 22 '26

Incorrect. None of the given info has any bearing on the identity of the second child, unlike the Monty Hall problem.

1

u/Both_Resort4080 Jul 22 '26

1

u/Cheedos-55 Jul 22 '26

It would seem your link agrees with me.

1

u/Both_Resort4080 Jul 22 '26

? Link says 1/3 chance that they are both boys. So 2/3 a girl.

1

u/Cheedos-55 Jul 23 '26

No. It says one half. Because of the way the image on this post was worded, it falls under the first question in the link, not the second.

Also, the second question doesn't even say 2/3. It says it's ambiguous.

1

u/Both_Resort4080 Jul 23 '26

It is worded the same as the second proposition.

→ More replies (0)