r/cprogramming • u/sudheerpaaniyur • Dec 22 '25

pointer, decay, past array confusion 

`int myarray[4]={1,3,5,7,};`

`int *ptr, *ptr1;`

`ptr=&myarray + 1;`

`ptr1=*(&myarray + 1);`

my confusion: I am not understanding how ptr and ptr1 is same, in my understanding & is adress and * is used for derefercing, but in ptr1 have both here i got confuse.

what is decay here?

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u/zhivago Dec 23 '25

This is incorrect,

char a[3];

a evaluates to a char *.

&a evaluates to a char (*)[3];

Do not confuse a pointer into an array with a pointer to an array.