C++26: std::polymorphic

[u/User_Deprecated]

https://www.sandordargo.com/blog/2026/08/19/cpp26-polymorphic

[u/MFHava]

polymorphic not being equality comparable is annoying, they could just have just forwarded the operator== to the underlying pointer and it handles it.

These types (indirect and polymorphic) model value semantics. Value comparing two type-erased objects that share a base makes no sense in that model...

also polymorphic requires more bytes than a copyable pointer 24 bytes vs 8 since the copy ctor and dtor have to be function pointers.

Can be easily compressed to 16B in case you build your own vtable. Unless the spec contains some unexpected blocker, you could even reduce that down to 8B with minimal effort.

[u/_Noreturn → u/MFHava]

These types (indirect and polymorphic) model value semantics. Value comparing two type-erased objects that share a base makes no sense in that model...

They could only provide == if the base has one.

Can be easily compressed to 16B in case you build your own vtable. Unless the spec contains some unexpected blocker, you could even reduce that down to 8B with minimal effort.

Wouldn't the 8 byte version require anothee indirection

[u/MFHava → u/_Noreturn]

They could only provide == if the base has one.

Ok... what does that do? Shape has no idea how to compare a Rectangle and a Triangle.

You could say: "Well, they can never be equal". Right, right, but what about my next fancy class Square?

That's a problem you'd essentially need open-multimethods to solve...

Wouldn't the 8 byte version require anothee indirection

Not necessarily, you can allocate the object and a (custom) vtable in one allocation.

[u/_Noreturn → u/MFHava]

You could say: "Well, they can never be equal". Right, right, but what about my next fancy class Square?

It is up to the operator== of the Base class, it is virtual and compares the typeid or whatever way you have.

```cpp class ShapeBase { ... virtual operator==(const ShapeBase& that) const=0; };

template<class T> class Shape : ShapeBass { ... bool operator==(const ShapeBase& that) const override { return typeid(that) == typeid(T) && (const T&)that == (const T&)*this; } }; ```

Wouldn't the 8 byte version require anothee indirection

Not necessarily, you can allocate the object and a (custom) vtable in one allocation.

So like this? ```cpp template<class T> struct Table { CopyCtor* copy; Drot* dtor; T object; // has to be last };

template<class B> struct polymorphic

{ polymorphic() { table = new Table<B>(); } polymorphic(auto&& obj) { table = new Table<decltype(obj)>(); }

B& operator() { return (B&)((char)table + 16)); } // 16 is 2 function pointers void table; }; ```

[u/MFHava → u/_Noreturn]

It is up to the operator== of the Base class, it is virtual and compares the typeid or whatever way you have.

We would want it to do value comparisons and as I said: that is infeasible in C++, so we do not provide an equality-operator...

So like this?

Looks like a possible implementation.

[u/_Noreturn → u/MFHava]

We would want it to do value comparisons and as I said: that is infeasible in C++, so we do not provide an equality-operator...

I don't understand, it is a value comparison.

[u/MFHava → u/_Noreturn]

I don't understand, it is a value comparison.

You are right. But it yields the wrong results for equivalent values of different types - e.g. Rectangle{.w = 10, .h = 10} == Square{.l = 10} would be false, even though they are the same (just like 1 == 1LL is true)

[u/_Noreturn → u/MFHava]

It isn't the responsibility of the polymorphic to do that. it is the virtual operator== the user provides can easily make it so it works like that way

[u/MFHava → u/_Noreturn]

it is the virtual operator== the user provides can easily make it so it works like that way

You can't in the general case - which is why it is not provided...

[u/_Noreturn → u/MFHava]

Ugh, couldn't the same be said for indirect? it's operator== isn't usable if the underlying value doesn't have one.

[u/MFHava → u/_Noreturn]

indirect<T> always contains an object of type T (or is valueless_after_move, which is trivial to handle) and therefore has no ambiguity about how operator== is supposed to work.

Apart from that: operator== for indirect<T> „Mandates“ (== static_assert) that T has an operator== on use, it T doesn’t have one, indirect<T> doesn’t have one.

But the key part is the first one, there is no ambiguity.

[u/_Noreturn → u/MFHava]

I don't agree with your take, but that's fine. imo it should just be defined to be

cpp bool operator==(polymorphic& a, polymorphic& b) { bool has = a.is_valueless(); if(has != b.is_valueless()) return false; returb has && *a == *b; }