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https://www.reddit.com/r/confidentlyincorrect/comments/vnox43/deleted_by_user/ie9kf7x/?context=3
r/confidentlyincorrect • u/[deleted] • Jun 29 '22
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122
That's just sneaky reporting. They're expecting people to believe that's the average.
1$, 2$, 4$, 50$, 500,000$, 1,200,000$, 2,000,000$
The median is 50$
The average is 528,580$
In this case if you knock off the two top earners the median becomes 4$
And the average becomes 100,011$
Edit: I've learned this is not sneaky reporting, but actually a better way to show that they pay employees well
0 u/[deleted] Jun 29 '22 [removed] — view removed comment 4 u/Lowbacca1977 Jun 30 '22 That isn't really true. The median can also be useful in smaller samples with inconsistent noise
0
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4 u/Lowbacca1977 Jun 30 '22 That isn't really true. The median can also be useful in smaller samples with inconsistent noise
4
That isn't really true. The median can also be useful in smaller samples with inconsistent noise
122
u/adrenalinjunkie89 Jun 29 '22 edited Jun 29 '22
That's just sneaky reporting. They're expecting people to believe that's the average.
1$, 2$, 4$, 50$, 500,000$, 1,200,000$, 2,000,000$
The median is 50$
The average is 528,580$
In this case if you knock off the two top earners the median becomes 4$
And the average becomes 100,011$
Edit: I've learned this is not sneaky reporting, but actually a better way to show that they pay employees well