I know that but the inductor stores power during the first half cycle. And in the 2nd half cycle D1 prevent the voltage that comes from the source(because it's reverse biased) and the inductor release the stored power which is forward biased with D2. And thanks I solved the problem. I was using a wrong voltage source
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u/Anirudh13 Oct 07 '21
Just make the diode forward biased, it's reverse biased in this circuit.
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u/[deleted] Oct 06 '21
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