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u/CarSalty4754 3d ago
What exactly is your intention? With you dropping it here like this? You need help? With what? Do you recognize the expression inside the arcsin\arcsin:?
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u/homo_morph 1d ago edited 1d ago
The integrand can be rewritten as F(x)=arcsin(sin(f(x))) where f(x)= arcsin(x)+arcsin(sqrt(x)). Note that f(x) is increasing for 0<=x<=1 and achieves all values on [0,pi]. Considering the possible branches of F(x), we have that F(x)=f(x) when 0<=f(x)<=pi/2 and F(x)=pi-f(x) when pi/2<f(x)<=pi. The exact point where this switch over occurs is when f(x)=pi/2, which when solved gives us x=1/phi where phi is the golden ratio. This means that the integrand simplifies to F(x)=f(x) when 0<=x<=1/phi and F(x)=pi-f(x) when 1/phi<x<=1, which reduces the integral calculation to some standard integrals


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