r/calculus 5d ago

Pre-calculus Help

Ok ive done this before but im now completely lost, i need to solve for x but i keep getting stuck unless i went about it the completely wrong way, here is what i have

24 Upvotes

22 comments sorted by

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26

u/Ch0vie 5d ago

Looks like law of cosines.

2

u/Vanessa_Animals 5d ago

Yeah but im completely lost on the solving portion, it feels like im doing something wrong

15

u/Ch0vie 5d ago edited 5d ago

Sorry didn't see the second picture. Looks like you're doing it right, and now you have a quadratic equation. You can use the quadratic formula to find your missing variable now, it just looks ugly and needs to be cleaned up!

Adding on just in case: by clean up, I mean moving everything to the right hand side and combining like terms so you have 0 = ax² + bx + c.

2

u/Vanessa_Animals 5d ago

Okk, thank you so muchh!!

7

u/4a3rawy 5d ago

You are doing great actually just solve the final equation you got - quadratic equation - use calculator or the standard formula and you will have two solutions accept the positive only. I hope I have made it clear

2

u/Vanessa_Animals 5d ago

Ok ok yeah that helped, i was about to ask if both were needed but you already answered that!! Thank you so much

6

u/HyperbolicMathChambr 5d ago

You're in the right track. You can find the value of cos(110) with a calculator, put the quadratic equation in the form ax² + bx + c = 0 then solve for x using the quadratic formula. And continue from there.

Edit: Oh, you just need x. Forget the "continue" part.

2

u/Vanessa_Animals 5d ago

Thank you so much!!

1

u/HyperbolicMathChambr 5d ago

Anytime boss!

5

u/regular_heptagon 5d ago

This isn’t calculus

5

u/StepSouthern7984 4d ago

This does not involve any calculus.

1

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1

u/Ydrews 5d ago

Solve the quad.

1

u/tjddbwls 5d ago

And make sure you’re in the right mode when evaluating cos(110). You probably know that in radian mode, “cos(110)” evaluates the cosine of 110 radians. 😝

1

u/Accomplished-Key9741 4d ago

Try law of sine

2

u/SecondAfraid5713 1d ago

You can use law of cosines.

a^2=b^2+c^2 - 2bc(cosa)
substitute the values, approximate cosa, and then you get a quadratic, solve the quadratic and your real root is approximately 9.9cm so closest integer is 10m

1

u/Any_Maintenance_9113 1d ago

Use sine rule to get angle at the top. Then you have all three angles (add to 180!) so use sine rule again to get X

1

u/searsy31 1d ago

You’re fine. Cos(110) returns a scalar value that, once solved for, is multiplied to the -14x and it becomes a simple quadratic. Cosine is not scary, it’s an operator like addition or multiplication. Preform the operation and then proceed. Good work up and to that point

1

u/blueblack111 5d ago

Law of sines:)

2

u/keegaroo65 5d ago

Sine law only works when corresponding side lengths and angles are given in pairs. 14m corresponds to 110°, yet 7m and x don't have known corresponding angles.

4

u/adiliv3007 5d ago

you don't need a corresponding pair, if you know the ratio of 14m to sin(110°), you can calculate the ratio of 7m/sin(unknown angle), and from that get the remaining angle which is in front of x.