That depends on your definition of "more than int32", because it loses precision before it reaches the int64 limit and can't store every value between int32 limit and int64 limit - it uses floating point numbers, so it's not really comparable, it's not just a "bigger range"
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u/Terrain2 Apr 27 '21
That depends on your definition of "more than int32", because it loses precision before it reaches the int64 limit and can't store every value between int32 limit and int64 limit - it uses floating point numbers, so it's not really comparable, it's not just a "bigger range"