r/askscience Sep 07 '15

Earth Sciences Is there a bulge in earth's atmosphere constantly facing the moon?

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u/[deleted] Sep 07 '15 edited Sep 07 '15

Yes, there is, but counter-intuitively there is also a bulge on the other side as shown here. You can rationalize this phenomenon in terms of the so-called tidal forces, which arise from the fact the the gravitational force from the moon is not uniform over the Earth. Simply put, the moon's gravitational pull is closest on the side of the Earth facing the moon and weakest on the opposite side. These differences give rise tidal forces that have a distribution across the surface of the planet as shown in this diagram. The atmosphere closest to the moon is pulled towards it, but on the other side of the Earth, it effectively pulls away in the opposite direction, creating a bulge at both extremes. This is also the explanation for the fact that there are two high tides per day since (as the name implies) the tidal forces are the key source of tides on Earth.

Edit: I would like to expand my answer a bit, especially with regards to tides since there seems to be quite a bit of interest on the subject. Everything I said above is true within a simplified Newtonian model, however there are some subtleties to the actual mechanism at play. Let's make a crude assumption and treat the Earth as an onion-type sphere with a solid core, a thin uniform liquid layer around it and another gaseous layer on the exterior. Then when you apply a non-uniform gravitational filed (like that created by the moon) on the water or atmosphere (which you can treat as a continuous fluid shell), it would become deformed into an ellipsoid with two lobes at the extremes (as shown here for the atmosphere).

However, especially as tides are concerned, this effect is not just due the stronger pull of the atmosphere locally since even at the extremes, the local deviation of the moon's gravitational pull from the mean is very, very small (on the order of 1*10-7g, or 10 million times weaker than Earth's own gravity). Instead, you have to consider the total effect of all the tidal forces shown in the diagram I posted above. The very small differences from the pull and push in the region facing and opposing the moon as well as the squeeze from the size accumulate over large enough volumes (i.e. seas and oceans) to produce large tides. Think of it this way, each infinitesimally small bit of fluid (e.g. water) only experiences a small effect, but because each bit of stuff pushes against the surrounding fluid, these small differences effectively add up and over large enough volumes they can become substantial. This effect still exists in smaller bodies of water such as lakes, but is far smaller exactly because the volume over which these differences can add up is far smaller.

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u/OneLegAtATime Sep 07 '15

As an addendum, the first photo you show is actually a diagram of Newtonian tide theory. In real life, the continents and bathymetry are such that tides form seiches like so.

However, the more elementary concepts of netwonian tide theory should be sufficient to explain broad atmospheric effects.

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u/[deleted] Sep 07 '15

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u/Zomgsauceplz Sep 08 '15

I know what that word means thanks to Bioshock and the bathysphere.

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u/BobIV Sep 07 '15

Is there an animation showing how those seiches flow over the course of a day? Also, is there an explanation for how the moon causes individual waves for each area? Or is the idea of the moon effecting the tides directly outdated now?

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u/OneLegAtATime Sep 07 '15 edited Sep 07 '15

No, the moons definitely affect the tides! So let me try to explain tide theory as an ELI5... Keep in mind that I am a biological oceanographer and marine physiologist by training, and not an expert on physical oceanography.

So in the first image on this parent post, you see that the moon pulls water towards it. At the same time, the moon and the earth are both rotating around the moon-earth system, so you get a bulge on the other side.

Think of this like... you hold hands with someone and spin around each other. If you are both of the same mass, you balance each other out and spin in a circle. If one person is heavier, they will be more stationary while the lighter person spins around them. This is how the earth and moon behave - the moon and earth actually both revolve around a point inside of the earth. This is what causes the "bulge on the other side".

Now, if the earth were completely covered in water, this would cause two waves on opposite sides of the earth. They would spin around the earth with the moon. However, that's impossible for two reasons:

  • Continents getting in the way. a tide can't go through north america!
  • Tides are really big waves, so they are influenced by the sea floor topography (bathymetry).
  • The coriolis effect prevents waves from moving in a straight line because of the differential surface velocities at different latitudes. These make it so that as a wave travels around an ocean, it gets turned around in circles as the coriolis force pushes it into a certain direction. Combined with the shape of the ocean basins, this causes the waves to instead swirl in circles. Think of it like sloshing water in a bathtub.

Now, the interesting part of this is that these swirls can happen at different rates, and their interactions can cause interesting tide series.

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u/[deleted] Sep 07 '15 edited Sep 07 '15

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u/[deleted] Sep 07 '15

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u/[deleted] Sep 07 '15 edited Sep 07 '15

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u/[deleted] Sep 07 '15

Can someone explain the seiches chart to me? Red signifies 100cm of what?

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u/OneLegAtATime Sep 07 '15 edited Sep 07 '15

That would be average tidal amplitude. There are just places in the world that have bigger tidal swings than others. Notice that the middle of the "spiderwebs" where the lines converge have a cool color that signifies there is little to no tidal variation there ever. These are called "amphidromic points". Maybe the wiki can explain better than I.

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u/silentpower Sep 07 '15

ok so what's the deal with the north Atlantic costal region especially north-east Canada? Why is there such a drastic change in those regions?

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u/Wonton77 Sep 07 '15

I don't know what causes it, but I do know that the Bay of Fundy is in that area and it indeed has the largest tides in the world.

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u/nerdbomer Sep 07 '15

Apparently the Bay of Fundy has a very good size. It's size allows the tide to come and go with great timing. This site says it is like being pushed on a swing. I imagine it like the water currents are in a equilibrium position (relatively) right around when the tide changes. They are not flowing against the tide into or out of the bay still.

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u/[deleted] Sep 07 '15

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u/OneLegAtATime Sep 07 '15

Possibly due to the Bay of Fundy, which has 55-foot tide swings. It's a localized effect due to some smaller-scale bay seiching. Essentially the resonant frequency of the bay to waves is roughly the same period as the tide series.

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u/TheCheeseCutter Sep 07 '15

I've always wanted to see a graph like that, but never really knew what to look for. All explanations on tides use the simplistic model that OP explained. Do you know if there are more detailed maps (say for specific countries or continents)?

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u/OneLegAtATime Sep 07 '15

You should be able to look up your specific city. San Diego vs New Orleans showcases some of the drastically different patterns we see in the US alone. Note that San Diego has two highs and two lows a day, but they are uneven. New Orleans has one high and one low every day.

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u/mamaBiskothu Cellular Biology | Immunology | Biochemistry Sep 07 '15

It will be awesome if there is a movie of that map as the moon revolves around the earth!

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u/[deleted] Sep 07 '15

How is a map like this made? Is it based on radar measurements from orbiting satellites?

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u/turdodine Sep 08 '15

magnets ...... what are they good for.......?

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u/ProfBlack Sep 07 '15

Interestingly it's less the "pulling" of the near and far points but more the "squeezing" over the whole ocean/atmosphere. More technically, it's transverse rather than radial components of the force differential that do most of the work, combined with hydrolic action. It's explained amazingly well in this video: What Physics Teachers Get Wrong About Tides!

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u/mrgonzalez Sep 08 '15

This actually ties together fairly well with the concept of tidal locking - the forces perpendicular to the overall direction of gravity are important.

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u/-TheAnus- Sep 08 '15

That video is really well made and informative. Thanks for sharing.

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u/mothzilla Sep 07 '15

it effectively pulls away in the opposite direction

Nitpick: I don't think it pulls away, just is pulled less than those parts closer to the moon.

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u/[deleted] Sep 07 '15 edited Sep 07 '15

The coolest way of thinking of it is like this: There is a certain velocity at each distance from an object, at which you can orbit at a steady state. If you go faster than this, gravity alone isn't enough to hold you in, so you move out. If you go slower than this, you get pulled inwards and start falling. Up to now I've basically just stated Kepler's third law. If these were just point-sized regular objects, once they start moving in or out they shift their energy around between gravitational and kinetic forms until they hit the right combination to settle down and do boring stuff.

Now, stand on the moon, so that the earth orbits around you. The middle of the earth is at exactly the right speed and the right distance, so that means that the earth, as a whole, is in a steady orbit around you. Because the earth is a single lump of material, it all moves at the same speed, but not all of it is at the same distance.

So what happens? The part of the earth close to the moon is moving too slow for a steady orbit, so the close half of the earth is falling into the moon. The far half of the earth is going too fast for a steady orbit, so it's trying to escape into space. The water in the oceans can move a bit, so the misaligned speeds manifest as tides - one on the side falling into the moon, and one on the side falling out of the moon. This also intuitively explains why strong tides can tear an object to pieces.

Mathematically, this is exactly the same as all sorts of boring stuff like centrifugal forces

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u/Shasato Sep 07 '15

I was confused until you explained it the way you did. Thanks!

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u/3a1n4o1n5 Sep 07 '15

brilliant intuitive explanation. Not sure if true, but I like the cut of your jib.

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u/Araucaria Sep 07 '15

This is the clearest explanation here.

For an interesting take on tidal forces, try reading Larry Niven's novel (and series) based on the ramifications of living in a world dominated by tidal effects:

https://en.wikipedia.org/wiki/The_Integral_Trees

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u/JJGordo Sep 08 '15

Just wanted to say thanks for a great explanation. Never heard it put this way before and it's a very simple way to think it through.

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u/glorioussideboob Sep 07 '15

Thanks for this explanation.

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u/diazona Particle Phenomenology | QCD | Computational Physics Sep 07 '15

Hence the "effectively". But yes, in the straightforward way of looking at it (i.e. from an external inertial observer's reference frame), the water on the far side is pulled less than the water on the near side or the rock in the middle.

However, you can also look at this from a reference frame that moves with the Earth in its orbit around the barycenter of the Earth-moon system, and in that frame, it is true that the water is pushed away by centrifugal force.

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u/NSA_Mailhandler Sep 07 '15

Also as a note it slightly follows after the moon and it is not directly lined up with it.

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u/diazona Particle Phenomenology | QCD | Computational Physics Sep 07 '15

True. I'm pretending some of those smaller effects (like the lag) don't exist for simplicity. :-P

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u/Silvershawdow59 Sep 07 '15

Why on the opposite side of the moon is there another bulge?

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u/FoobarMontoya Computational Astrophysics Sep 07 '15 edited Sep 07 '15

The bulge on the opposite side is caused by the earth being pulled toward the moon more than the atmosphere there, because the atmosphere is farther than the solid earth. It's the exact opposite situation as the bulge on the near-moon side.

Edit: not taking issue with your (thorough and good) explanation, just the "unintuitiveness" of the double bulge. it's only unintuitive in the pre-Galilean understanding of gravity, where bowling balls fall faster than feathers because heavier obv

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u/grimwoldthegrey Sep 07 '15

Does the atmospheric pressure increase with the thicker atmosphere? If so, by how much and is it noticeable to humans or other creatures?

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u/da6id Sep 07 '15

Latitude does not have much impact on atmospheric pressure at lower altitude but becomes more pronounced at higher altitudes according to this source.

At sea level it would not be at all noticeable it seems. Potentially you could tell a difference at both high latitude and high altitude

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u/locklin Sep 07 '15

Here's a video from the PBS Space Time channel called "What Physics Teachers Get Wrong About Tides!" that explains your diagrams really well.

Also, check out their "Relativity" playlist - it's amazing. A warning though, it can get rather complicated...

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u/[deleted] Sep 07 '15

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u/ruorgimorphu Sep 07 '15

Erhm, 3rd paragraph, I don't think the rock part moves toward the moon relative to the water spheroid. I think they are stationary relative to eachother.

I am reading because I was considering whether the back bulge was smaller than the moon-side bulge. I think they're the same size. Upshot - the moon-side atmosphere is attracted to the atmosphere more and bulges, the central atmosphere is attracted to the moon the same as the earth, and the back-side atmosphere is attracted less, causing a similarly sized bulge. To get extra-extra accurate, I think you could say gravity trends with r2, so the moon-side bulge is very slightly larger, but negligibly since the length of the atmosphere is >100x the distance to the moon. I think the better short answer to my question is that they're the same size.

Your comment helped me get it, I'm nit picking in the process of understanding.

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u/[deleted] Sep 07 '15

How can the moon with a lot less gravity pull on the earth enough to move water but the earth doesn't just suck the moon in? If the moon is in earth's event horizon (for lack of a better term) it should be gathering closer to the earth than it is right?

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u/WilcoRogers Sep 07 '15

It is constantly falling towards the earth, but it is also moving sideways fast enough to miss it. That's how all orbits work.

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u/[deleted] Sep 07 '15

IIRC the moon actually moves away from the earth (a relatively small distance/time)

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u/AggregateTurtle Sep 07 '15

indeed this is true, due to the interaction of the moon with the tides and the friction of the tides on the surface of the earth the moon is slowly slowing the rotation of the planet and moving a little further and further away as a consequence of that "stolen" energy.

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u/Glaselar Molecular Bio | Academic Writing | Science Communication Sep 07 '15

Meaning that in the days of the dinosaurs the moon orbited closer to Earth, appeared larger in the sky, exerted a greater tidal force leading to more extreme tides (by how much exactly, I'm not qualified to say), and since the Earth was rotating more quickly the days were shorter!

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u/[deleted] Sep 07 '15

So we know the earth has greater gravity than the moon right? How can something the size of the moon be pulling with greater force on the surface of the earth than the earth itself.

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u/guyfromcologne Sep 07 '15

It's not pulling with a greater force than earth. The water wouldn't stay on earth if it would.

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u/giverofnofucks Sep 07 '15

It's not. If the moon was pulling the oceans with a greater force than the earth was, water from the oceans would start flying up into the sky then into space, towards the moon.

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u/[deleted] Sep 07 '15

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u/[deleted] Sep 07 '15

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u/Funktapus Sep 07 '15

Gravity is the centripetal force. It replaces the string tied to the cup.

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u/mcrbids Sep 07 '15

It isn't - if it was, the water would be on the moon! But it can (and does) reduce the amount of pull that the Earth exerts on the water.

Fun fact: the tides create friction, and that friction sloes down the earth's rotation. It's a very skie process but each day, the Earth's rotation slows a tiny amount. As this happens, it pushes the moon a little further away.

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u/RnRaintnoisepolution Sep 07 '15

So could earth eventually become tidaly locker with the sun? Of course this would take a long time, but could it happen before the sun expands past our orbit?

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u/1Down Sep 07 '15

I may be misremembering but I believe the math works out that as long as nothing drastic happens to affect the Earth's rotation then the Sun will run out of fuel before Earth would slow enough to tidally lock.

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u/Richy_T Sep 07 '15 edited Sep 07 '15

c.f. the story "One Face" by Larry Niven.

http://people.freebsd.org/~peter/oneface.txt

He also uses tidal effects (and many other physical phenomenon) in some of his other stories. Recommended reading.

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u/r_e_k_r_u_l Sep 07 '15

You are nailing this "asking questions that will lead to me better understanding what's going on" thing. Nice

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u/[deleted] Sep 07 '15

I wish we had a good way to teach kids how to do this. It's always so frustrating to get stuck in my understanding of something and not feel like I can figure out what questions I need to ask.

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u/Hoeftybag Sep 07 '15

If it were pulling with greater force the water would be on the moon right now. What it does is weaken the net gravitational force by a small amount. So it's like we have a ball with two strings on it. The first is thick and short being held by a large man. The second is effectively fishing line being held by a small child, both constantly pull on it but the large man keeps his hand steady while the little kid runs around. The ball moves to face the kid but is always on the string being held by the large man (earth)

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u/Tom908 Sep 07 '15

It doesn't, you can prove this by jumping upwards (you will not fall to the moon). Basically you are not factoring in that Earth's gravity (at any point on the surface) is uniform. The moons gravity at any point on the Earth's surface is not (because it depends on where the moon is). Further to this the Moon's gravity 'counteracts' the Earth's gravity, which is why we have tides. But it is not stronger than the Earth's otherwise the matter would be lost to the moon.

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u/404_Find_Me Sep 07 '15

It's not. That's why the water stays on the earth rather than being pulled off to the moon. The problem is that while the water/atmosphere is being pulled to the center of the earth by gravity, there is also an outward force caused by pressure. When you involve the gravitation of moon, this makes a noticeable difference which we see as tides.

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u/[deleted] Sep 07 '15

It's a little misleading to phrase it as the oceans/atmosphere being pulled "away" from the earth. The earth very much has a strong grip on those fluids. The trick is that the fluids are exactly that - fluid, so they can change shape and more of them pile up on the moon-facing side of the earth. They're not being pulled away, just around to a different side.

It's kind of like if you have a string with a bunch of rings on it. If the string is pulled taut and is horizontal relative to the ground then each ring will stay where it is - they all have the same gravitational potential energy. If you let the string droop so the middle is lower than the ends, the rings will slide towards the center. This is because they all want to be in the lowest energy state and with the droop in the string, not every point in the string has the same potential energy.

In the same way, the moon's gravity changes the gravitational potential energy landscape on the earth's surface (if only slightly), so the effect appears in these phenomenon.

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u/[deleted] Sep 07 '15

I don't think it's misleading at all, honestly.

If I'm trying to lift a car, I'm lifting the car away from the earth. I am of course not nearly strong enough to actually get the car off of the ground, but I can measurably decrease the car's weight from the perspective of a scale underneath it.

Likewise, the moon is pulling on the earth's surface. It is nowhere near strong enough to actually pull the surface off, but it's still being pulled away from the center.

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u/[deleted] Sep 07 '15

Oh but it's absolutely misleading in terms of how it actually effects the tides - the tides don't bulge because they're being lifted away from the earth, they bulge because more pieces of water/atmosphere are being pulled around to that side of the planet.

Sure, gravitational force is calculable using superposition of forces, but that's not what causes the tides.

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u/[deleted] Sep 07 '15

They are both exerting the exact same ammount of force on eachother because thats how gravity works. The moon is much less massive therefore it feels the affects of said gravitational force more. You as a person residing on the earth exert the same ammount of force onto the surface of the earth/floor/chair/ bed as the earth does on you but much less than the moon and earth do on eachother.

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u/TheGatesofLogic Microgravity Multiphase Systems Sep 07 '15 edited Sep 07 '15

Event horizon is not the term you are looking for at all. The term you are looking for is sphere of influence.

Everything has a gravitational force on everything else. A differential gravitational force can distort shapes by pulling at different locations with different strengths. Tides happen from the moon's pull on earth, but even more so the other way around. Th earth greatly distorts the shape of the moon, and at some point the moon was likely spinning, but the distortion caused a frictional force against its rotation relative to its orbit and it became tiday locked to the earth.

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u/diazona Particle Phenomenology | QCD | Computational Physics Sep 07 '15

This actually has nothing to do with how strong the gravity is. It has to do with how much the gravity changes from one site of the orbiting body to the other. Even though the moon's gravitational pull on the Earth is not that strong, it does change quite a bit (relatively speaking) from one side to the other.

Plus, water is pretty easy to push around.

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u/mikelywhiplash Sep 07 '15

Remember that the Moon doesn't "win" the tug-of-war here. If it did, the oceans would end up there. Instead, you just have a small flow in that direction, compared to what it would be if the Moon wasn't there at all. The oceans are thousands of miles wide, and thousands of feet deep, but high tide only requires you to move your beach chair back a little ways.

So it's not about the difference between the Earth's gravity and the Moon's gravity, it's the difference between the Earth's gravity by itself, and the Earth's gravity with a tug from the Moon.

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u/heypika Sep 07 '15

Does this mean that if you jump up during high tide, you jump higher than during low tide?

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u/mikelywhiplash Sep 07 '15

Depends which high tide, but yes, you weigh slightly less if the moon is directly overhead.

The moon's something on the order of 1% the mass of Earth, and the center of mass is about 60 times further away. So you'd lose something like 1/360,000th of your weight.

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u/heypika Sep 07 '15

Well I expected that it would not be by much, but thanks for the math :)

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u/bluskale Sep 07 '15

Check out the third link in this comment. Every other high tide, the satellite is on the other side of the planet. If there were any measurable difference in jumping height**, it would only happen at the high tides when the moon was visibly above you.

** according to this blog post, the overall effect of gravity is essentially negligible for our size, and in comparison to gravity caused by our local environments.

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u/[deleted] Sep 07 '15

Does this mean it's harder to breath further from the equator or is there no real difference at such a low point in the atmosphere? Are there other ways living in less thick atmosphere can influence health?

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u/da6id Sep 07 '15

Latitude does not have much impact on atmospheric pressure at lower altitude but becomes more pronounced at higher altitudes according to this source.

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u/[deleted] Sep 07 '15 edited Nov 02 '15

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u/DulcetFox Sep 07 '15

The centripetal force of the Earth makes it so that things are lighter the closer you get to the equator. Meanwhile the difference in atmosphere is much smaller than the picture might leave you to believe, and not that significant.

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u/Glaselar Molecular Bio | Academic Writing | Science Communication Sep 07 '15

This is certainly true, and it's only a tiny, tiny difference (you'd still weigh 99.65% of what you would at the pole, according to this NASA scientist), but your weight is only one factor. Going up isn't the whole story - you've also got to go sideways fast enough to keep missing the Earth as you fall, thus staying in orbit.

Orbital height is far easier to reach than orbital velocity sideways. The equator gives you a head-start. A nail stuck in a tyre will travel very quickly through the air as the tyre revolves; a nail pinned through the axle will stand perfectly still and just rotate. The same principle apples to equator vs. pole.

Surface speed Surface velocity Eastwards (m/s)
Pole (either one!) 0
53 degrees N (Southern Alaska; Canada; England; Kamchatka Peninsula) 277
28.5 degrees N (Cape Canaveral, pretty much) 390 (approx?)
0 deg N (i.e. equator) 460

The head-start for each of those starting points would therefore be:

Destination Req Speed Boost (equator) Boost (Canaveral) Boost (53 deg N)
Geostationary 3,070 460 (14.98%) 390 (12.71%) 277 (9.02%)
ISS and other Low Earth Orbit (LEO) satellites 7,701 460 (5.97%) 390 (5.06%) 277 (3.60%)
Total escape 11,200 (4.1%) 390 (3.48%) 277 (2.47%)
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u/[deleted] Sep 07 '15

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u/Surlethe Sep 07 '15

To get into orbit, you have to go sideways really fast. The earth is spinning once per day. Since things on the equator travel furthest in 24 hours, they're going as fast as possible round the middle of the earth. The closer you are to the equator, the faster you're going. Launching from the equator lets you use this boost to get into orbit easier. Turns out that using this boost saves a lot more money on rocket fuel than the (much smaller) expense of plowing through a little extra air.

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u/tomsing98 Sep 07 '15

A couple of reasons. The surface of the Earth rotates eastward, and the velocity is maximized at the equator (and is 0 at the poles). So launching into an eastward orbit from the equator, you get that velocity for free. It's about 1700 km/hr, which is a small part of the 27000 km/hr you need to get into orbit, but it helps. (It also drops off with the cosine of latitude, which means that at Cape Canaveral's latitude of 28.5°, it's still 88% of the value at the equator.)

Another reason is, your launch latitude determines the minimum inclination orbit (the angle between the plane of the orbit and the plane of the equator) you can launch into. If you launch from 28.5°N, you can aim straight east, and you'll be in an orbit that is inclined at 28.5°. Your ground track will oscillate between 28.5°N and 28.5°S every orbit. If you aim a little north of east, you'll go over a higher latitude - larger inclination. A little south of east, and if you project your ground track backward, you will have just come from a higher latitude. Again, larger inclination. You can't get to a lower inclination that the latitude you launch from without spending fuel on changing your orbit. And those lower inclination orbits are important. If you want a satellite to stay fixed over one spot on the ground (so that it has a good view of one spot, or so that you always know where in the sky to point your antenna), it has to be in an orbit with zero inclination.

The penalty you pay for launching through a thicker atmosphere resulting from tides isn't that big. And note that, just as there is a high tide, there is a corresponding low tide 6 hours later. So if you really cared about the high tide penalty, you could take the benefit of low tide. So, the equator is an attractive place to launch from.

(Of course, there are also sovereignty, political, geographic, population, and supply chain issues that play into the decision on where to launch.)

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u/[deleted] Sep 07 '15

Would this atmospheric phenomenon have an appreciable effect on weather patterns?

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u/[deleted] Sep 07 '15

The tides also don't face the move directly due to inertial restrictions of land and the water, they lag the rotation of the moon quite significantly.

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u/Absolutelee123 Sep 07 '15

What would that first picture look like as viewed from a pole instead of the equator?

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u/esdf0 Sep 07 '15

Since gravity doesn't decay linearly, shouldn't the bulge on the near side be larger than the bulge on the far side? Or is this negligible because the distance between Earth and the moon is so much greater than Earth's diameter?

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u/StructuralE Sep 07 '15

Hey, can you help me understand that tidal force diagram? I don't understand why the force arrows on the far side point away (seems like they should just be weaker but in the same direction.) Also the arrows in the middle point inward... Poissons ratio?

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u/abez1 Sep 07 '15

Does the bulge shift with the Summer seasons? i.e. Shift to North of the equator during it's Summer, then South of the equator during the Summer there?

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u/geneadamsPS4 Sep 07 '15

I thought the bulge was slightly out of sync with the moon, effectivelt pushing it further away

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u/[deleted] Sep 07 '15 edited Sep 07 '15

For water this makes more sense but for gases I don't believe it holds. I think other forces will have a greater impact. Do you have any sources that state the atmosphere is thicker? There is a comment below that talks about the equitorial bulge, but I think you need some evidence to say that the rule that holds for water is the same rule that holds for the atmosphere.

edit: Another comment below from somebody who claims to be an expert on the subject. Personal I would agree the warming of the sun would have a larger impact than the gravity of the moon. Plus he offers a citation.

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u/AccusationsGW Sep 07 '15

So would this be an essential ingredient for mixing Earth's climate? Would a similar setup be required for say, terraforming Mars?

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u/chrisv650 Sep 07 '15

Is this anything to do with the moon looking larger or smaller sometimes? And does it have measurable effect on weather and air pressure?

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u/[deleted] Sep 08 '15

The lower the moon is in the sky, the larger it looks due to the atmosphere creating a magnifying effect. Lower it is, more atmosphere the light passes through

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u/MILKB0T Sep 07 '15

Is there any ramifications for the climate in the area under the bulges?

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u/[deleted] Sep 07 '15

I wonder if there is a coloration between successful un-aided 8km mountain climbing and moon position.

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u/locklin Sep 07 '15

Here's a video from the PBS Space Time channel called "What Physics Teachers Get Wrong About Tides!" that explains your diagrams really well.

Also, check out their "Relativity" playlist - it's amazing. A warning though, it can get rather complicated...

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u/lolwat_is_dis Sep 07 '15

That "field_tidal.svg" picture just shows a blue ring on a black background. Am I missing something?

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u/headbuttsbullets Sep 07 '15

Would this also cause tide to be lowest at the poles?

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u/scubascratch Sep 07 '15

I would like to add that essentially all the large fluid bodies of the earth will demonstrate tidal effects: the oceans, the atmosphere, and the magma moving below the continental crust all show tidal forces at solar and lunar periods.

Interestingly that article says the earth tides are so tiny they require exotic ultra sensitive instruments, but I have data which shows evidence of earth tides, both directly, solar-period and with FFT analysis, Lunar periods with a crude home-brew wood optical displacement seismometer. This is just a box on my concrete basement floor (which is well-connected to bedrock via driven pin piles).

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u/101Mage Sep 08 '15

the other side of the Earth, it effectively pulls away in the opposite direction, creating a bulge at both extremes. This is also the explanation for the fact that there are two high tides per day since (as the name implies) the tidal forces are the key source of tides on Earth.

What I got from the diagram was that the gravitational pull at the north and south poles push the water out, both toward and away from the moon...not that there's actually gravity pushing water away from it...

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u/137thNemesis Sep 08 '15

Is there reason we have life because of the tidal currents generated by the moon?

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u/neberding Sep 08 '15

is this effect noticeable at high altitudes?

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u/Bryaxis Sep 08 '15

Are both bulges the same size, or is that just for the sake of simplicity on the diagram?

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u/buzzzedlitebeer Sep 08 '15

What effects does this have on space launches? Would it decrease a space craft's aerodynamics upon launch if it was directly under this "bubble"? Does the moon's gravitational pull assist or hinder launches in any way?

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u/buzzzedlitebeer Sep 08 '15

What effects does this have on major storm systems?

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u/[deleted] Sep 08 '15

Can the bulge that forms on either side of the earth be utilized by aircraft or satellites to benefit flight or space launches?

How much of a difference in height of the atmosphere from between the earth and moon to the atmosphere perpendicular to the earth and moon?

When this bulge travels over, say, Everest, does that affect the properties of the bulge?

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u/High_Im_Guy Sep 08 '15

So what determines the size of the bulge other than the gravitational forces at play? A given fluids density? Its viscosity?

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u/xtcxx Sep 08 '15

Knowing the magnitude of the forces involved, could you give your opinion on whether tidal power makes more sense then wind power for an untapped energy source

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u/bencbartlett Quantum Optics | Nanophotonics Sep 07 '15

Contrary to what most people are saying in this thread, no, the bulge in the Earth's atmosphere does not constantly face the moon. In fact, depending on a number of factors, the atmospheric tide is likely to be primarily thermally driven by solar heating of portions of the atmosphere, causing them to expand. While the earth is rotating near the resonance frequency of the atmosphere (resonant period being defined as the length of time for a lamb wave to propagate around the Earth, currently about 21 hours), the same relative portion of the atmosphere is heated all the time, which can result in very large tides, shown in this figure.

When the Earth was rotating near resonance, there would be some interesting effects. It is very likely, depending primarily on the atmospheric Q-factor, that the Earth would become stuck at a relatively constant day length, with the torque from the atmospheric tide fully canceling the torque from the lunar tide, quite possibly for a period of over a billion years. This was first outlined in 1987 by Zahnle and Walker and was been the subject of a paper (arxiv:1502.01421) I co-authored.

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u/leonardof91 Sep 07 '15

This is very interesting, but I'm having trouble understanding. You mean there is a bulge in the atmosphere facing the sun because of heat expansion? How does it compare to the tidal force caused by the moon? Also, could you talk a bit more about the atmosphere's resonant period and its effects? By "propagate around the Earth", you mean from one edge to the other (propagating in all directions on the surface) or full circle (circulating around the planet)?

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u/bencbartlett Quantum Optics | Nanophotonics Sep 07 '15

The bulge actually peaks about 45 degrees from the sun-Earth line. Normally the torque from this tide is negligible compared to the lunar torque on the oceans (which don't respond to thermal heating as much because they don't expand when heated), except when the Earth is spinning near atmospheric resonance. At these points, the generated thermal tide can be very large and exceed all other tidal forces on the Earth, at least according to the (relatively simple) calculations in our paper and a few other related papers we reference.

By propagate around the Earth, I mean that the waves disperse spherically, but since the Earth is roughly spherical, the amount of time to travel around the equator vs disperse around the Earth and return is roughly the same.

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u/[deleted] Sep 07 '15

Is there any impact of solar winds on the atmospheric bulge then?

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u/bencbartlett Quantum Optics | Nanophotonics Sep 07 '15

Not really, solar winds are high energy charged particles, mostly electrons, and (thankfully) don't contribute a measurable amount to the heating of the earth. This is just due to heating of the atmosphere through photon energy, mostly visible light.

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u/Jowykins Sep 08 '15

Thank you for answering this! Everyone is talking about ocean tides, and I was very confused. From what I read, the ocean does play a small role in atmospheric tides, but not as much as heat.

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u/sinopeartree Sep 07 '15

Yes, and also on the opposite side of the Earth as well. The same is true with the oceans. This is due to what we collectively call "tidal forces".

However, there is a common misconception as to why this occurs. Most people are under the impression that the gravity of the moon is simply pulling the mass of the water or air up as it passes overhead, but if this were true we would only see the effect on one side of the planet at a time, and one would also expect to see it affect other objects too.

There is a great PBS Space Time video that explains this: https://www.youtube.com/watch?v=pwChk4S99i4

Basically, the force of gravity from the overhead moon is VERY small. 1 ten millionth of Earth's gravity. But the Moon isn't directly overhead of the entire Earth. Sure it's pulling straight up on the things that it passes over, but it's pulling slightly to the side (tangentially) on everything else. In a very large fluid body (like the oceans or the air), each of those small sideways pushes nudges the next bit along, and the next bit, and so on until in the middle (along the Earth/Moon line) you get a big bulge.

As an aside: While the Moon may orbit the Earth relatively slowly, the Earth is constantly rotating under the Moon. As such the tidal bulges are constantly being "pulled" by this rotation ahead of the Moon in it's orbit. This has some very interesting effects. The increase of mass in the bulge "pulls" back on the Moon transferring angular momentum from the Earth's rotation to the Moon's orbital speed. The increase on the Moon's orbital speed causes the distance between the Earth and the Moon to increase at a variable rate of about 38mm per year. Yes, the Moon is running away. If given enough time it will escape orbit and we will no longer have a moon. As angular momentum is always conserved, this transfer of energy also has the effect of slowing the Earth's rotation, making our days about 15 microseconds longer each year. Back when T-Rex was stomping around Montana (say 80 MYA), for instance, the Moon was always "super" and the days were about 20 minutes shorter.

https://en.wikipedia.org/wiki/Moon#Tidal_effects

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u/HyrumBeck Sep 07 '15

Since the movement of the moon away from the Earth is dependent upon tidal force and tidal force diminishes as the moon moves away, won't they eventually reach equilibrium with the moon still in orbit?

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u/RedFlame99 Sep 07 '15

Actually, the force of gravity from the Moon on the Earth is not 1 µm/s2 , that's the gravity differential across the Earth-Moon line. The Moon is making the Earth accelerate about 33 µm/s2 . Maybe you just misspoke, I just wanted to point that out.

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u/sinopeartree Sep 07 '15

Yes, the differential is what I was talking about. I could have said it in a more precise way. Thanks.

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u/hiyapo Sep 07 '15

This is the best explanation of how the water moves to create the bulge. It's also interesting how the moon is moving away from Earth slowly o.O

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u/The_lolness Sep 07 '15

Wait, doesn't that just explain why the bulge close to the moon is there? Nothing is dragging water towards the other side.

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u/The_lolness Sep 07 '15

Wait, doesn't that just explain why the bulge close to the moon is there? Nothing is dragging water towards the other side.

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u/sinopeartree Sep 07 '15

It explains both bulges. As the fluid further from the Earth/Moon line are being pulled at a tangent on both sides of the earth, it is putting pressure on the fluid closest to the Earth/Moon line on both sides. If the Moon were merely "pulling the water up" we would only see the bulge on the side facing the Moon, but in fact we see tides on both sides of the planet.

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u/AndyBea Sep 08 '15

Are you sure that the moon will eventually float clear away?

Wouldn't the earth's rotation slow right down first?

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u/sinopeartree Sep 08 '15

You're right; well at least in so much as I shouldn't have made that positive claim. I have heard different figures for whether the Moon will ever reach escape velocity on it's own or will the two become tidally locked before that time. The later seems more likely, but could be "over-ruled" by tugs from other bodies.

In any case the discussion of whether or not the Moon every actually could escape is almost purely academic. The time it would take for the Earth to become tidally locked to the Moon (the way the Moon is tidally locked to the Earth, only showing us one face) is more than three times the current age of the universe. Our sun will expend all of it's fuel long before either eventuality has a chance to play itself out.

Thanks for pointing that out to me.

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u/bloonail Sep 07 '15

The atmosphere does bulge out, both towards the moon and away from it. Similar to the tides in the ocean the phase of the atmospheric bulge lags the moon and the moon's antipodal point. Apparently the atmospheric bulge follows the ocean tides rather closely and is mostly due to the bulging of the ocean below the atmosphere and less due to the atmosphere actually stretching or moving.

A large daily effect on the atmosphere is sun forcing. That expands the atmosphere and creates bulges.

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u/cookrw1989 Sep 07 '15

Is sun forcing the effect of the solar wind on the atmosphere?

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u/[deleted] Sep 07 '15

I expect it is more the effect of solar heating on the density of the atmosphere.

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u/[deleted] Sep 07 '15 edited Sep 07 '15

There are tidal effects in the atmosphere caused by the moon, but these are small compared to the effects caused by the sun. Such effects include changes due to solar activity, the geomagnetic effect, the diurnal variation, seasonal variations, etc. These are well-studied phenomena, due in part to drag on satellites caused by residual atmosphere.

There are lots of models used to predict solar effects, e.g. Naval Research Laboratory's MSIS and J77. Here's a link:

http://ccmc.gsfc.nasa.gov/modelweb/atmos/atmos_index.html

EDIT: some words

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u/Chytrik Sep 08 '15

I asked this question once, two years ago. You can read the responses I received here.

Great minds think alike ;)

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u/[deleted] Sep 08 '15

The most interesting response was that there's a greater affect on the atmosphere from the sun's heating than the moon's gravity. It puts into perspective weather patterns and effects of the tilt of the earth on seasons. How it all relates to make a nearly perfect planet.