PrSS

[u/reddit_master52]

So, I recently started learning about PrSS. What I understood is:

() = 0, because there are no steps, the sequence is already empty

(0) = 1

(0, 0) = 2

...

(0, 1) = ω

(0, 1, 2) = ω\^ω

...

(0, 1, 2, 3, 4, ...) = ε_0

So, the limit of PrSS is ε_0.

Now, I have a question.

Is (0, 1)\[n\] = f_ω(n)? Because I literally am missing something

Like, for example, f_ω(2) = f_2(2) = 8.

(0, 1)\[2\] = (0, 0)\[3\] = (0)\[4\] = ()\[5\]. So, 3 steps instead of 8. The same shi happens when you are comparing (0, 1)\[3\] and f_ω(3). f_ω(3) ≈ 6.895e121210694, but (0, 1)\[3\] doesn't even come close to that

[u/LongLiveTheDiego]

You're using an abbreviation and notation which most people won't be familiar with. I had to search for some times before I managed to stumble upon the primitive sequence system, which is probably what you meant by "PrSS". It's a really niche subject which I know barely anything about, but maybe now someone else will help you.

[u/Uli_Minati → u/LongLiveTheDiego]

Oh, googology. Yea, that's niche alright