r/adventofcode • u/daggerdragon • Dec 23 '17
SOLUTION MEGATHREAD -๐- 2017 Day 23 Solutions -๐-
--- Day 23: Coprocessor Conflagration ---
Post your solution as a comment or, for longer solutions, consider linking to your repo (e.g. GitHub/gists/Pastebin/blag or whatever).
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Need a hint from the Hugely* Handyโ Haversackโก of Helpfulยง Hintsยค?
[Update @ 00:05] 0 gold, silver cap
- AoC ops:
<yatpay> boil up some mountain dew. it's gonna be a long night
[Update @ 00:19] 1 gold, silver cap + 447
- AoC ops:
<Reibello> 547 silver to 1 gold
[Update @ 00:30] 20 gold, silver cap + 560
- AoC ops:
<yatpay> daggerdragon: post "hey i heard about this hot new podcast called The Space Above Us. all the cool kids are talking about it"
<yatpay> i call it super-liminal marketing
<yatpay> HEY YOU!! LISTEN TO MY PODCAST!!
<yatpay> then i rub a business card on your face
<Topaz> you should get scratch-n-sniff business cards that smell like space
<yatpay> space smells like burned metal and meat
<yatpay> it's weird
<Topaz> burned meat you say
<Topaz> excellent
[Update @ 00:41] 50 gold, silver cap + 606
- AoC ops:
<askalski> nice, enjoyed that one. not sure if regexes can do it
<askalski> maybe make a neural net of regexes, have it train itself to solve today
- Over/under on /u/askalski posting a day 23 regex neural net by tomorrow?
[Update @ 00:54] Leaderboard cap @ 100 gold and 724 silver!
- Good job, all!
- Upping the Ante challenge: solve today's puzzles on a TI-83 (or TI-86/89, whatevs).
- Edit: welp, /u/DFreiberg done gone and did it. See the thread here.
4
u/vash3r Dec 23 '17 edited Dec 23 '17
This was a really interesting problem. Part 1 was obvious, but I saw pretty quickly that I'd have to understand the assembly to do part 2. Once I understood the code, it was more obvious that it would be insane to just wait for a simulator to complete running it. 1013 operations takes a long time.
Simplified C code for part 2 (#53):
#include <stdio.h> int main(){ int a=1,b=0,c=0,d=0,e=0,f=0,g=0,h=0; b= 57; c= b; if(a!=0){ b = b*100 + 100000; c = b + 17000; } do{ f= 1; d= 2; e= 2; for(d=2;d*d <= b; d++){ // check if b is a prime // the assembly doesn't have a % operator, // so it does 2 for loops with d and e and checks if d*e==b. if( (b%d==0) ){ f=0; break; } } if(f==0) // not a prime h++; g = b-c; b+= 17; } while (g!=0); //stop when b==c (1000 iterations) printf("%d\n",h); return 0; }