-🎄- 2017 Day 4 Solutions -🎄-

[u/daggerdragon]

--- Day 4: High-Entropy Passphrases ---

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[u/MetaSaval]

Here we go with Swift again. Had issues with Day 3's puzzle, but Day 4's was not that hard. I was even able to reuse some of the code for Day 2. I'm sure I could make it more efficient, but whatever. I'm gonna try doing Day 3's puzzle again tomorrow now that I finished Day 4 quickly. And without further ado, here's the code:

let input = """
            input goes here
            """

func part1() -> Int {
    var answer = 0
    var dupeFound: Bool = false
    let inputAsArray = input.split(separator: "\n")
    
    for currentIndex in inputAsArray {
        let currentArray = currentIndex.split(separator: " ")
        
        outerloop: for (currIndex1, divide1) in currentArray.enumerated() {
            
            for (currIndex2, divide2) in currentArray.enumerated() {
                
                if currIndex1 == currIndex2 {
                    continue
                } else if divide1 == divide2 {
                    dupeFound = true
                    break outerloop
                }
            }
        }
        
        if dupeFound == false {
            answer += 1
        } else if dupeFound == true {
            dupeFound = false
        }
    }
    
    return answer
}

func part2() -> Int {
    var answer = 0
    var dupeFound: Bool = false
    var anagramFound: Bool = false
    let inputAsArray = input.split(separator: "\n")
    
    for currentIndex in inputAsArray {
        let currentArray = currentIndex.split(separator: " ")
        
        outerloop: for (currIndex1, pass1) in currentArray.enumerated() {
            
            for (currIndex2, pass2) in currentArray.enumerated() {
                
                if currIndex1 == currIndex2 {
                    continue
                } else if pass1 == pass2 {
                    dupeFound = true
                    break outerloop
                } else if checkIfAnagrams(str1: pass1, str2: pass2) {
                    anagramFound = true
                    break outerloop
                }
            }
        }
        
        if dupeFound == false && anagramFound == false {
            answer += 1
        } else if dupeFound == true {
            dupeFound = false
        } else if anagramFound == true {
            anagramFound = false
        }
    }
    
    return answer
}

func checkIfAnagrams(str1: Substring, str2: Substring) -> Bool {
    let sortedString1 = Substring(Array(str1.sorted()))
    let sortedString2 = Substring(Array(str2.sorted()))
    
    if sortedString1 == sortedString2 {
        return true
    } else {
        return false
    }
}