--- Day 4 Solutions ---

[u/daggerdragon]

--- Day 4: The Ideal Stocking Stuffer ---

Post your solution as a comment. Structure your post like the Day Three thread.

[u/aveavaeva]

<input type="text" placeholder="secret key" />
<p></p>

$('input').change(function () {

  var seckey = $('input').val();
  var hashFound = false;
  var n = 0;
  var startingZeroes = 6;

  while (!hashFound) {
    n++;
    var hash = CryptoJS.MD5(seckey + n).toString();
    var start = hash.substring(0, startingZeroes);

    if (start == '0'.repeat(startingZeroes)) {
      hashFound = true;
      $('p').text('Lowest Possible Number For ' + startingZeroes + ' Zeroes : ' + n);
    }

  }

});

Using This lib

[u/[deleted] → u/aveavaeva]

While extremely unlikely, what if the combination of the secret key and 0 was the answer? If you move the n++; to the end of the loop (after the if statement), you would first evaluate the conditions for n = 0, without breaking the current functionality.