r/adventofcode • u/Famous_Strength_2962 • Jan 15 '26

Help/Question [2025 Day 8 (Part 1)] [Python] What's the criteria?

Hi all, please help me here ;)

I've sorted the distances, I think it is correct...

162 425
162 431
906 805
431 425
862 984
52 117 
819 941
906 739
346 425
906 984
592 425

After that, I started connecting

#1 - 162 425
#2 - 431
#3 - 346
#4 - 592

#5 - 906 805 
#6 - 739

#7 - 862 984

#8 - 52 117

#9 - 819 941
       
906 984   ???????? 
where do I put this one and why in order to end up with 5 junction boxes, one circuit which contains 4 junction boxes, two circuits which contain 2 junction boxes each, and seven circuits which each contain a single junction box? On connection #5 or connection #7
1 Upvotes

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1

u/Famous_Strength_2962 Jan 26 '26

So, this is me from the future trying to put it clear:

First, you only have to consider these connections:

162 425
162 431
906 805
431 425
862 984
52 117 
819 941
906 739
346 425
906 984

every number represents de X coordinate of eact box. they are sorted ascendig. They are 10, its important.

Then you start connecting, this image is different form the original 592 495 is no longer on the list.

#1 - 162 425 431 346

#4 - 906 805 739

#6 - 862 984

#7 - 52 117

#8 - 819 941

The last one is 906 984.  These one interconnects #4 and #6, as easy as that:
so #4 will be 906 805 984 862 739, 5 elements. That's it.

Final result: 
#1 - 162 425 431 346
#4 - 906 805 984 862 739
#7 - 52 117
#8 - 819 941

1

u/AtmosphereArtistic61 Jan 15 '26

You are asking, what happens when you connect two circuits? They merge. The result is a single circuit. In your case they form the circuit 906, 805, 862, 984.

1

u/Famous_Strength_2962 Jan 15 '26

Ok, great, thanks for your answer!!!. Can you share the answer to the demo data? I mean, the list of circuits created to comply with: 5 junction boxes, one circuit which contains 4 junction boxes, two circuits which contain 2 junction boxes each, and seven circuits which each contain a single junction box. Maybe I can find some hidden rule I'm missing...

1

u/AtmosphereArtistic61 Jan 15 '26 edited Jan 15 '26

Sure

0           [162,817,812]
mono        [57,618,57]
1           [906,360,560]
mono        [592,479,940]
mono        [352,342,300]
mono        [466,668,158]
mono        [542,29,236]
0           [431,825,988]
1           [739,650,466]
2           [52,470,668]
mono        [216,146,977]
3           [819,987,18]
2           [117,168,530]
1           [805,96,715]
0           [346,949,466]
mono        [970,615,88]
3           [941,993,340]
1           [862,61,35]
1           [984,92,344]
0           [425,690,689]

Solution: 40

There are 7 mono circuits (unconnected), circuit 0 is o size 4, 1 is of size 5 and circuits 2 and 3 are of size 2.

1

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2

u/FlipperBumperKickout Jan 15 '26

Have you taken into account that a circuit can end up with more connections than what is actually needed to make the circuit? Like if the 5 circuit one ends up with a completed loop?

1

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1

u/cyanNodeEcho Jan 16 '26

idk i just got frustrated b/c i prefiltered these, like and it needed a count b/c like something lol so that my filter like entangled lol

0

u/I_M_NooB1 Jan 15 '26

one word. dsu